Question

我在下面有一个小查询，我希望每个HOUSE_ID的计数和LOCATION_ID分组，但不是LOCATION_ID分组，因为HOUSE_ID＆＃39; s是不同的。无论HOUSE_ID是什么，我都希望LOCATION_ID对HOUSE_ID进行计数。

QUERY

SELECT 
COUNT(HOUSE_ID) AS Count,
LOCATION_ID,
ZONE,
AREA
FROM TABLE
WHERE SITE_ID = 'ABC'
AND LOCATION_ID NOT LIKE ('%LAND%')
GROUP BY LOCATION_ID, HOUSE_ID, ZONE, AREA

预期结果

_____________________________
|Count|LOCATION_ID|ZONE|AREA|
|¯¯¯¯¯|¯¯¯¯¯¯¯¯¯¯¯|¯¯¯¯|¯¯¯¯|
|  4  |  LOCA     | 2  |  1 |
|  7  |  LOCB     | 6  |  2 |
|  3  |  LOCC     | 3  |  1 |
|  9  |  LOCD     | 5  |  7 |
|  6  |  LOCE     | 7  |  4 |
|  2  |  LOCF     | 2  |  1 |
|  8  |  LOCG     | 7  |  5 |
|  7  |  LOCH     | 9  |  1 |
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

实际结果

_____________________________
|Count|LOCATION_ID|ZONE|AREA|
|¯¯¯¯¯|¯¯¯¯¯¯¯¯¯¯¯|¯¯¯¯|¯¯¯¯|
|  1  |  LOCA     | 2  |  1 |
|  1  |  LOCA     | 6  |  2 |
|  1  |  LOCA     | 3  |  1 |
|  1  |  LOCA     | 5  |  7 |
|  1  |  LOCA     | 7  |  4 |
|  1  |  LOCA     | 2  |  1 |
|  1  |  LOCA     | 7  |  5 |
|  1  |  LOCA     | 9  |  1 |
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Answer 1

您必须从group by子句中删除HOUSE_ID。如果没有源数据，我只能猜测您还需要ZONE和AREA列的聚合函数，例如MAX。尝试以下解决方案：

SELECT 
COUNT(HOUSE_ID) AS Count,
LOCATION_ID,
MAX(ZONE),
MAX(AREA)
FROM TABLE
WHERE SITE_ID = 'ABC'
AND LOCATION_ID NOT LIKE ('%LAND%')
GROUP BY LOCATION_ID

Answer 2

得到它，需要数（*）!!

SELECT 
COUNT(*) AS Count,
SUM(AREA) AS AREA
LOCATION_ID,
ZONE,
FROM TABLE
WHERE SITE_ID = 'ABC'
AND LOCATION_ID NOT LIKE ('%LAND%')
GROUP BY LOCATION_ID, ZONE

Oracle SQL计数字段由另一个字段分组

2 个答案: