嘿,我试图在合并然后在unio中将两个不同结果集的结果相加。目的是获得每种描述的计数差异。
使用下面的代码我从MS ACCESS的union语句中得到一个错误。 或者如果我在加入中获得错误后添加额外的parenthis。
任何想法????
select description, sum(CP)
from
(select description, count(description)
*-1 AS CP
from status
where date_loaded between #1/1/2014# and #2/1/2014#
group by description)
Union all
(select description, count(description) AS CP
from status
where date_loaded between #1/1/2014# and #3/1/2014#
group by description)
按说明分组
答案 0 :(得分:2)
您不能在子查询中执行union
(在MS Access的许多问题中)。幸运的是,您可以使用条件聚合执行所需操作:
select description,
count(*) - sum(iif(date_loaded between #1/1/2014# and #2/1/2014#, 1, 0)) as diff
from status
where date_loaded between #1/1/2014# and #3/1/2014#
group by description;
我认为以下内容也符合您的要求:
select description,
sum(iif(date_loaded between #2/2/2014# and #3/1/2014#, 1, 0)) as newest
from status
where date_loaded between #1/1/2014# and #3/1/2014#
group by description;