Question

我一直试图通过多线程创建几个二维数组。每个线程都会生成一个小的2-D数组。所有的二维将被合并，这就是我遇到问题的地方。我在"//!this is causing error"方法的底部评论了SimulatingMethod。请分享您的见解。谢谢。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Threading;

namespace ThreadExample
{
    class Program
    {
        static void Main(string[] args)
        {
            double[,] randSims;
            randSims = SimulatingClass.SimulatingMethod();
        }
    }

    class SimulatingClass
    {
        public static double[,] SimulatingMethod() 
        {
            int rowCount = 9;
            int columnCount = 1;

            int NumberOfCores = System.Environment.ProcessorCount;
            int RowsForEachThread = rowCount / NumberOfCores;

            Thread[] arrayOfThread = new Thread[NumberOfCores];
            DataStuff[] dataStuff= new DataStuff[NumberOfCores];
            for (int i = 0; i < NumberOfCores; i++)
            {

                dataStuff[i] = new DataStuff(RowsForEachThread, columnCount);
                arrayOfThread[i] = new Thread(new ThreadStart(dataStuff[i].UpdateMatrixData));
                arrayOfThread[i].Name = "Thread" + i;
                arrayOfThread[i].Start();
            }

            for (int i = 0; i < NumberOfCores; i++)
            {
                arrayOfThread[i].Join();
            }

            //start combining arrays from different threads
            var list = new List<double[,]>();
            for (int m = 0; m < NumberOfCores; m++)
            {
                list.AddRange(dataStuff[m]); //!this is causing error
            }

            //trying to convert list back to array
            double[,] array3 = list.ToArray();  //!this is causing error

            return array3;

        }

    }

    class DataStuff
    {
        public double G;
        public double[,] M;
        public long steps, trials;

        public DataStuff(long _steps, long _trials)
        {
            M = new Double[_steps, _trials]; // <- M is created in the constructor
            G = 60;
            steps = _steps;
            trials = _trials;
        }

        public void UpdateMatrixData()
        {
            for (int i = 0; i < steps; i++)
            {
                for (int j = 0; j < trials; j++)
                {
                    M[i, j] = i + j;
                }
            }
        }

    }
}

Answer 1

您应该按如下方式指定属性：

list.Add(dataStuff[m].M);

这是因为dataStuff[m]的类型为DataStuff，但预期类型为double[,]的列表项。

如果我理解正确，您需要一个合并的2D数组。尝试最初使用所需尺寸声明它：

double[,] array3 = new double[rowCount, columnCount];

在处理后将数据从dataStuff数组复制到它：

for (int m = 0; m < NumberOfCores; m++)
{
    Array.Copy(dataStuff[m].M, 0, array3, m * columnCount * RowsForEachThread, dataStuff[m].M.Length);
}
return array3;

您根本不需要list。

请注意，您有可能与舍入相关的问题：

int RowsForEachThread = rowCount / NumberOfCores;

当rowCount无法被NumberOfCores整除时，您应该处理这种情况。

组合通过多个线程创建的数组

1 个答案: