我有两个表格(如下所示),名为Merge_Codes&因素。我正在尝试编写一个查询,该查询从因子表中获取不同的国家/地区,并将其连接到Merge_Codes表并返回该区域。
请查看底部的结果表,看看我的意思。我试图在一个查询中执行此操作但是在解决方案附近没有任何地方,正如您可以从下面的sql中看到的那样。
SELECT * FROM Merge_Codes
INNER JOIN ON
(SELECT DISTINCT Country FROM Factors)
Merge_Codes表
Region Country
EU Germany
EU France
EU Italy
Asia Japan
Asia Hong Kong
NA Canada
NA USA
SA Brazil
SA Peru
SA Chile
因素表
Factor Country
ABC Germany
ABC Germany
ABC Japan
ABC USA
ABC USA
ABC Hong Kong
结果
Country Region
Germany EU
Japan Asia
USA NA
Hong Kong Asia
答案 0 :(得分:3)
select mc.*
from Merge_Codes mc
join (select distinct Country FROM Factors) f
on mc.Country = f.Country
答案 1 :(得分:2)
select
MC.Country,
MC.Region
from
(SELECT DISTINCT Country FROM Factors) DC
INNER JOIN Merge_Codes MC ON MC.Country = DC.Country