Question

我有 4列的 MySQL 表： completedtasks，duration，date和educationDepartment 。我的第一个目标是在我的特定日期显示我的条目以工作日的名称。我用以下查询完成了这个：

SELECT DAYNAME(date) AS DAY,
       completedtasks,
       duration,
       educationDepartment
FROM programm_completedtask;

现在我想总结一下我所拥有的信息，到星期几。假设我有一个包含以下条目的表格，例如：

+-----------+-----------------------+----------+---------------------+
| Day       | completedtasks        | duration | educationDepartment |
+-----------+-----------------------+----------+---------------------+
| Monday    | Some stuff to do      |        6 | A Department        |
| Tuesday   | Some other stuff to do|        8 | Another Department  |
| Wednesday | Some other stuff to do|        6 | Test Department     |
| Thursday  | Being lazy            |        8 | Another Test        |
| Friday    | A completed task      |        8 | Another Test        |
| Monday    | Some entry            |        2 | A Test              |
| Wednesday | Test entry            |        2 | Another Test        |
+-----------+-----------------------+----------+---------------------+

我尝试了几个查询，但那些没有给我我想要的结果。当我使用 GROUP BY 时，它只是给了我表中的条目，如下所示：

+-----------+-----------------------+----------+---------------------+
| Day       | completedtasks        | duration | educationDepartment |
+-----------+-----------------------+----------+---------------------+
| Monday    | Some stuff to do      |        6 | A Department        |
+-----------+-----------------------+----------+---------------------+

此查询：

SELECT DAYNAME(date) AS Day,
       completedtasks,
       duration,
       educationDepartment
FROM programm_completedtask
WHERE DAYNAME(date)
LIKE "Monday";

给了我以下结果。

+-----------+-----------------------+----------+---------------------+
| Day       | completedtasks        | duration | educationDepartment |
+-----------+-----------------------+----------+---------------------+
| Monday    | Some stuff to do      |        6 | A Department        |
| Monday    | Some entry            |        2 | A Test              |
+-----------+-----------------------+----------+---------------------+

我的目标是获得结果，如下所示：

+-----------+-----------------------+----------+---------------------+
| Day       | completedtasks        | duration | educationDepartment |
+-----------+-----------------------+----------+---------------------+
| Monday    | Some stuff to do,     |       6,2| A Department, A Test|
|           | Some entry            |          |                     |
+-----------+-----------------------+----------+---------------------+

所以，我想总结一个特定工作日的条目，我希望它在一行中。我希望这在某种程度上是可能的。我非常感谢你的帮助！

Answer 1

SELECT DAYNAME(date) as `Day`,
        GROUP_CONCAT(completedtasks ) as completedTasks,
        GROUP_CONCAT(duration ) as duration ,
        GROUP_CONCAT(educationDepartment ) as educationDepartment  ,
FROM tableName
GROUP BY DAYNAME(date)

无需指定SEPARATOR，因为默认为逗号字符

Answer 2

这应该有效：

SELECT DAYNAME(date) AS Day, 
group_concat(completedtasks separator ',') as completedtasks, 
group_concat(duration separator ',') as duration, 
group_concat(educationDepartment separator ',') as educationdepartment 
FROM programm_completedtask
group by dayname(date);

请参阅此答案：How to use GROUP BY to concatenate strings in MySQL?

按天汇总MySQL表条目

2 个答案: