我在这里学习java,所以当我编写一个简单的程序时,每次尝试编译时都会出错。这是我得到的错误:
Trivia.java:14: error: cannot find symbol
ret = sc.nextline();
^
该计划如下:
import java.util.Scanner;
class GameStart {
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
String ret;
byte qnum;
String ans;
String correct = "Awesomely correct!";
String wrong = "Darn it! Almost got it!";
System.out.println("Do you think you know your stuff?");
ret = sc.nextline;
if (ret.equals("yes") || ret.equals("Yes"))
{
System.out.println("Well, then let's test what you know! Choose a number from 1 to 5!");
qnum = sc.nextByte();
switch (qnum)
{
case 1:
System.out.println("In what year did the French Revolution start?");
ans = sc.nextline();
if (ans.equals("1789") || ans.equals("Seventeen eighty nine"))
{
System.out.println(correct);
}
else
{
System.out.println(wrong);
}
break;
case 2:
System.out.println("How many protons does a sodium atom have?");
ans = sc.nextline();
if (ans.equals("11") || ans.equals("Eleven"))
{
System.out.println(correct);
}
else
{
System.out.println(wrong);
}
break;
case 3:
System.out.println("What is 2^6*0.5-12?");
ans = sc.nextline();
if (ans.equals("20") || ans.equals("Twenty"))
{
System.out.println(correct);
}
else
{
System.out.println(wrong);
}
break;
case 4:
System.out.println("Which is the lowest numbered element in the periodic table?");
ans = sc.nextline();
if (ans.equals("Hydrogen") || ans.equals("hydrogen"))
{
System.out.println(correct);
}
else
{
System.out.println(wrong);
}
break;
case 5:
System.out.println("Which is the unit that measures Coulombs per second?");
ans = sc.nextline();
if (ans.equals("Ampere") || ans.equals("ampere"))
{
System.out.println(correct);
}
else
{
System.out.println(wrong);
}
break;
default:
System.out.println("Stick to the rules! 1-5!");
}
}
else
{
System.out.println("Not liking that attitude, I want to hear a big yes!");
}
}
}
正如我所提到的,我是Java的新手,所以你肯定会发现更多的错误,而且我的风格也是#34;可能很糟糕,所以欢迎所有的建议! :)
答案 0 :(得分:0)
您忘记在此行中添加()括号
ret = sc.nextline;
也是nextLine而不是nextline
更改ret = sc.nextline;
到
ret = sc.nextLine();
答案 1 :(得分:0)
使用以下
ret = sc.nextLine();
而不是
ret = sc.nextline;
答案 2 :(得分:0)
应该是这样的:
rc.next的→强>啉()
案例非常重要。
括号也是。
答案 3 :(得分:0)
你的case错了,你忘记了括号(你应该先调用hasNextLine()) -
// something like this (with a ternary)
ret = (sc.hasNextLine()) ? sc.nextLine() : null;
或
if (sc.hasNextLine()) {
ret = sc.nextLine();
} else {
ret = null;
}