Question

该程序将查找文本文件中的所有单词并计算每个单词的找到次数。我们对'＆＃34;字＆＃34;的定义将是相对粗糙的，将通过基于不是字母的字符分割线来完成。我知道有更简单的方法可以解决这个问题，但我们需要使用类和我尝试过的搜索方法。我无法弄清楚为什么它没有增加word中已经存在的wordList。我相信它要么完全跳过if (foundAt >=0，要么没有正确递增，我倾向于我的search方法错了，但我可以＆＃ 39;找出问题所在。感谢你的时间，非常感谢任何和所有的帮助。

public class Hmwk {

public static void main(String[] args) throws FileNotFoundException {
    int n=0;
    WordCount[] wordList= new WordCount[10000];
    Scanner words = new Scanner(new File("input.txt"));
    while (words.hasNextLine() && n < 10000)
    {
        String line = words.nextLine();
        String[] tokens = line.split("[^\\p{Alpha}]");
        for (int i=0;i<tokens.length;i++)
        {
            if (tokens[i].length()>0)
            {
                WordCount word = new WordCount(tokens[i]);
                int foundAt = search(wordList, word, n);
                if (foundAt >= 0)
                {
                    wordList[foundAt].increment();
                }
                else
                {
                    wordList[n]=word;
                    n++;
                }
            }
        }
    }
    //Arrays.sort(wordList);
    String alphabeticFileName = "alphabetic.txt";
    String frequencyFilename = "frequency.txt";
    PrintWriter output = new PrintWriter(alphabeticFileName);
    for (int i=0; i<n;i++)
    {
        output.println(wordList[i].toString());
    }
    output.close();
    //Sort on frequency somehow
    PrintWriter output2 = new PrintWriter(frequencyFilename);
    for (int i=0; i < n; i++)
    {
        output2.println(wordList[i].toString());
    }
    output2.close();


}
public static int search(WordCount[] list,WordCount word, int n)
{
    int result = -1;
    int i=0;
    while (result < 0 && i < n)
    {
        if (word.equals(list[i]))
        {
            result = i;
        }
        i++;
    }
    return result;
}

}
class WordCount
{
String word;
int count;
static boolean compareByWord;
public WordCount(String aWord)
{
    setWord(aWord);
    count = 1;
}
private void setWord(String theWord)
{
    word=theWord;
}
public void increment()
{
    count=+1;
}
public static void sortByWord()
{
    compareByWord = true;
}
public static void sortByCount()
{
    compareByWord = false;
}
public String toString()
{
    String result = String.format("%s (%d)",word, count);
    return result;
}
}

输出：

Peter (1)
Piper (1)
picked (1)
a (1)
peck (1)
of (1)
pickled (1)
peppers (1)
A (1)
peck (1)
of (1)
pickled (1)
peppers (1)

Answer 1

您的增量功能错误。你写过：

count =+1;

仅将计数设为1。要将计数增加1，请输入：

count += 1;

搜索对象问题

1 个答案: