Question

我正在使用API并将JSON数组解码为PHP数组，但是当我使用foreach循环时它没有给我特定的值。这是原始JSON数组的片段：

"playerCredentials": {
    "observerEncryptionKey": "blahblah",
    "dataVersion": 0,
    "playerId": 8675309,
    "serverPort": 0,
    "observer": true,
    "summonerId": 0,
    "championId": 0,
    "observerServerIp": "111.111.111.111",
    "gameId": 123456789,
    "observerServerPort": 4388,
    "lastSelectedSkinIndex": 0
  },

然后，我运行了这段代码：

$array = json_decode($json_array, true);

然后将上述内容变为：

    { ["playerCredentials"]=> array(11) 
    { 
    ["observerEncryptionKey"]=> string(32) "blahblah" 
    ["dataVersion"]=> int(0) 
    ["playerId"]=> int(8675309) 
    ["serverPort"]=> int(0) 
    ["observer"]=> bool(true) 
    ["summonerId"]=> int(0) 
    ["championId"]=> int(0) 
    ["observerServerIp"]=> string(14) "111.111.111.111" 
    ["gameId"]=> int(123456789) 
    ["observerServerPort"]=> int(4338) 
    ["lastSelectedSkinIndex"]=> int(0) 
    }

然而，当我运行这个foreach循环时：

foreach($array['playerCredentials'] as $stats) {
echo $stats['playerId'];
}

所有我得到的回报是82（我甚至不知道它来自哪里）。但是，如果我运行这个：

foreach($array['playerCredentials'] as $stats) {
    echo $stats."<br>";
}

我获得了整个数组中的所有信息：

blahblah
0
8675309
0
true
0
0
111.111.111.111
123456789
4338
0

我怎样才能获得一件呢？

{
  "playerCredentials": {
    "observerEncryptionKey": "blahblah",
    "dataVersion": 0,
    "playerId": 8675309,
    "serverPort": 0,
    "observer": true,
    "summonerId": 0,
    "championId": 0,
    "observerServerIp": "111.111.111.111",
    "gameId": 1347503269,
    "observerServerPort": 8088,
    "lastSelectedSkinIndex": 0
  },
  "dataVersion": 0,
  "gameName": "match-1347503269",
  "reconnectDelay": 0,
  "game": {
    "practiceGameRewardsDisabledReasons": {
      "array": []
    },
    "glmSecurePort": 0,
    "queuePosition": 0,
    "playerChampionSelections": {
      "array": [
        {
          "spell1Id": 4,
          "spell2Id": 7,
          "championId": 25,
          "summonerInternalName": "nameone",
          "selectedSkinIndex": 0,
          "dataVersion": 0
        },
        {
          "spell1Id": 12,
          "spell2Id": 4,
          "championId": 13,
          "summonerInternalName": "nametwo",
          "selectedSkinIndex": 0,
          "dataVersion": 0
        }
]

Answer 1

在循环中，$stats指的是数组中每个元素的值。我认为你正在寻找$array['playerCredentials']['playerId'];。如果你想迭代播放器的所有属性，你可以这样做：

foreach ($array['playerCredentials'] as $key => $value) {
    printf('%s => %s<br />', $key, $value);
}

Answer 2

您可以尝试这样

<?php
$json_array ='{
    "playerCredentials": {
        "observerEncryptionKey": "blahblah",
        "dataVersion": 0,
        "playerId": 8675309,
        "serverPort": 0,
        "observer": true,
        "summonerId": 0,
        "championId": 0,
        "observerServerIp": "111.111.111.111",
        "gameId": 123456789,
        "observerServerPort": 4388,
        "lastSelectedSkinIndex": 0
    }
}';


$array = json_decode($json_array, true);

foreach($array as $playerCredentials) {
echo $playerCredentials['playerId'];
}

<强>输出

8675309

demo

Answer 3

如果使用PHP＆gt;你可以这样做5.4：

<?php
$json='{
    "playerCredentials": {
        "observerEncryptionKey": "blahblah",
        "dataVersion": 0,
        "playerId": 8675309,
        "serverPort": 0,
        "observer": true,
        "summonerId": 0,
        "championId": 0,
        "observerServerIp": "111.111.111.111",
        "gameId": 123456789,
        "observerServerPort": 4388,
        "lastSelectedSkinIndex": 0
    }
}';


$playerCredentials = json_decode($json, true)["playerCredentials"];

foreach($playerCredentials as $key => $value) {
    echo "key: ".$key."\n";
    echo "value: ".$value."\n";
}

以下是演示：https://eval.in/137205

或者，如果使用PHP＆lt; 5.4，你将无法使用json_decode嵌套数组访问，所以你只需这样做：

<?php
$json='{
    "playerCredentials": {
        "observerEncryptionKey": "blahblah",
        "dataVersion": 0,
        "playerId": 8675309,
        "serverPort": 0,
        "observer": true,
        "summonerId": 0,
        "championId": 0,
        "observerServerIp": "111.111.111.111",
        "gameId": 123456789,
        "observerServerPort": 4388,
        "lastSelectedSkinIndex": 0
    }
}';


$result = json_decode($json, true);

foreach($result["playerCredentials"] as $key => $value) {
    echo "key: ".$key."\n";
    echo "value: ".$value."\n";
}

以下是演示：https://eval.in/137209

PHP - 解码JSON数组并在foreach循环中使用

3 个答案: