对此进行了大脑研究,发现了许多类似情况的例子,但解决方案似乎并不匹配。
我有两个数组是由不同数据库上的SQL查询构建的。
其中一个是格式化的:
$data = array([$sku] => array(['LocalSKU'] => $sku,
['Price'] => $msrp,
['Price2'] => $wholesale,
['Price3'] => $distributor,
['Price4'] => $map))
另一个数组格式如下:
$matchme = array([0] => array(['entity_id'] => $entity_id,
['sku'] => $sku,
['type_id'] => $type_id))
目前,我可以通过以下方式获取个人数据:
echo $matchme[0]['sku'];
echo $matchme[0]['entity_id'];
echo $matchme[0]['type_id'];
echo $data[$matchme[0]['sku']]['Price'];
echo $data[$matchme[0]['sku']]['Price2'];
echo $data[$matchme[0]['sku']]['Price3'];
echo $data[$matchme[0]['sku']]['Price4'];
但是,当我尝试合并两个数组中的匹配行时,我得到一个空数组。 $ data数组包含74个唯一的$ sku,而$ matchme是对数据库检查这些$ sku并返回包含61个元素的数组的结果。因此,组合数组应该有61个元素,并且基于$ sku匹配定价数据。
我是如何尝试构建组合阵列的,如果有人指出我做错了吗?
foreach($matchme as $key){
if(in_array($matchme[$key]['sku'], $data)){
$matched_luggage[$matchme[$key]['sku']][] = array(
'sku' => $matchme[$key]['sku'],
'entity_id' => $matchme[$key]['entity_id'],
'type_id' => $matchme[$key]['type_id'],
'MSRP' => $data[$matchme[$key]['sku']]['Price'],
'Wholesale' => $data[$matchme[$key]['sku']]['Price2'],
'Distributor' => $data[$matchme[$key]['sku']]['Price3'],
'MAP' => $data[$matchme[$key]['sku']]['Price4']
);
}
}
在上面的示例中,将$ key计算为0,[' sku']的值匹配。
------------------------被修改---------------------- ---
每个请求,这是print_r($ data)截断空间的结果:
Array
(
[12PK-TITANIUM-CR123A] => Array
(
[LocalSKU] => 12PK-TITANIUM-CR123A
[Price] => 11.76
[Price2] => 10.32
[Price3] => 0
[Price4] => 0
)
[AA-CLAMSHELL] => Array
(
[LocalSKU] => AA-CLAMSHELL
[Price] => 0.25
[Price2] => 0
[Price3] => 0
[Price4] => 0
)
[AAA-CLAMSHELL] => Array
(
[LocalSKU] => AAA-CLAMSHELL
[Price] => 0.25
[Price2] => 0
[Price3] => 0
[Price4] => 0
)
[AE-AEL280PI] => Array
(
[LocalSKU] => AE-AEL280PI
[Price] => 0
[Price2] => 0
[Price3] => 0
[Price4] => 0
) )
每个请求,这是print_r($ matchme)截断空格的结果:
Array
(
[0] => Array
(
[entity_id] => 693
[sku] => 12PK-TITANIUM-CR123A
[type_id] => simple
)
[1] => Array
(
[entity_id] => 2596
[sku] => AE-AEL480HL
[type_id] => simple
)
[2] => Array
(
[entity_id] => 2597
[sku] => AE-AEL600-T6
[type_id] => simple
)
[3] => Array
(
[entity_id] => 2598
[sku] => AE-AEWL2
[type_id] => simple
) )
根据请求,这是$ matched_luggage的理想结果:
$matched_luggage = array( [12PK-TITANIUM-CR123A] => array([sku] => 12PK-TITANIUM-CR123A,
[entity_id] => 693,
[type_id] => simple,
[Price] => 11.76,
[Price2] => 10.32,
[Price3] => 0,
[Price4] => 0))
每个匹配的sku附加一个数组。
答案 0 :(得分:2)
试试这个:
foreach ($matchme as $arrProduct) {
if (isset($data[$arrProduct['sku']])) {
$arrMerged[$arrProduct['sku']]=array_merge($arrProduct, $data[$arrProduct['sku']]);
}
}
print_r($arrMerged);
您的代码不起作用的原因在于:
if(in_array($matchme[$key]['sku'], $data)) [...]
in_array()
的作用是告诉您 needle (在您的情况下是SKU字符串)是否作为数组 haystack 的值存在(在您的情况下, $数据)。您实际上是在尝试将字符串与数组匹配,而不是另一个字符串。
您真正想要的只是将SKU字符串与$ data的键匹配,isset()
可能是最简单的方法。
答案 1 :(得分:0)
假设您的第一个数组为$first
,第二个数组为$second
foreach ($first as $key => $each) {
foreach ($second as $secondeach) {
if($secondeach['sku'] == $key) {
$first[$key] = array_merge($first[$key], $secondeach);
// unset since you do not want LocalSKU value anymore.
unset($first[$key]['LocalSKU']);
}
}
}
$first
是您想要的数组。