Question

如何组合这些行（注意：这只是一个更大文件的摘录）：

interface GigabitEthernet0/0
 no ip proxy-arp
interface GigabitEthernet0/0.202
 no ip proxy-arp
interface GigabitEthernet0/0.358
 no ip proxy-arp
interface FastEthernet0/0/1.26
 no ip proxy-arp
interface GigabitEthernet0/0
 no ip proxy-arp
interface GigabitEthernet0/0.202
 no ip proxy-arp
interface GigabitEthernet0/0.358
 no ip proxy-arp
interface FastEthernet0/0/1.26
 no ip proxy-arp
interface Loopback0
 no ip proxy-arp
interface Loopback1
 no ip proxy-arp
interface Loopback26
 no ip proxy-arp
interface GigabitEthernet0/0/0
 no ip proxy-arp

这样他们就像这样：

interface GigabitEthernet0/0 | no ip proxy-arp
interface GigabitEthernet0/0.202 | no ip proxy-arp
interface GigabitEthernet0/0.358 | no ip proxy-arp
interface FastEthernet0/0/1.26 | no ip proxy-arp
interface GigabitEthernet0/0 | no ip proxy-arp
interface GigabitEthernet0/0.202 | no ip proxy-arp
interface GigabitEthernet0/0.358 | no ip proxy-arp
interface FastEthernet0/0/1.26 | no ip proxy-arp
interface Loopback0 | no ip proxy-arp
interface Loopback1 | no ip proxy-arp
interface Loopback26 | no ip proxy-arp
interface GigabitEthernet0/0/0 | no ip proxy-arp

我尝试了一些我在网上找到的不同解决方案，但似乎没有一种解决方案适用于我的情况

Answer 1

粘贴可以做到：

paste -d '|' - - < file

Answer 2

试试这个sed one-liner：

sed 'N;s/\n/ | /;s/\r//g' file.txt

Answer 3

 awk '{printf "%s%s",$0,(NR%2?"|":"\n")}' file

Answer 4

while IFS= read line1 && IFS= read line2; do
    printf "%s | %s\n" "$line1" "$line2"
done < file.txt

我该如何组合这些线条

4 个答案: