Question

我正在尝试将地址转换为geocoordiantes。当我调用此函数并打印latlong值系统时，给我以下错误。

警告：file_get_contents（http://maps.googleapis.com/maps/api/geocode/json?latlng=Raiwind Road，Lahore，Pakistan，74.2306＆amp; sensor = false）[function.file-get-contents]：无法打开流：HTTP请求失败！第137行的C：\ wamp \ www \ temp \ yy.php中的HTTP / 1.0 400错误请求

代码如下：请妥善解决

      function getlatlong($address)  
          {   
      $Address = urlencode($address);
      $request_url = "http://maps.googleapis.com/maps/api/geocode/xml?address=".$Address."&sensor=true";
      $xml = simplexml_load_file($request_url) or die("url not loading");
       $status = $xml->status;
       if ($status=="OK") {
         $Lat = $xml->result->geometry->location->lat;
        $Lon = $xml->result->geometry->location->lng;
         $LatLng = "$Lat,$Lon";
          }
           return $LatLng;
              }
            $coord=getlatlong($source1);
             print $coord;

Answer 1

这对我有用：

<?php
  $Address = urlencode($Address);
  $request_url = "http://maps.googleapis.com/maps/api/geocode/xml?address=".$Address."&sensor=true";
  $xml = simplexml_load_file($request_url) or die("url not loading");
  $status = $xml->status;
  if ($status=="OK") {
      $Lat = $xml->result->geometry->location->lat;
      $Lon = $xml->result->geometry->location->lng;
      $LatLng = "$Lat,$Lon";
  }
?>

参考文献：

将地址转换为坐标

1 个答案: