我有一个字符串,它是我必须提取到数组中的规则组合。 AND
条件用逗号分隔,OR
移到下一个数组索引下面是我正在尝试的一些条件
(1 AND 2) AND (3 AND 4) => ["1,2,3,4"]
1 OR 2 => ["1","2"]
(1 OR (2 AND 3)) AND 4 => ["1,4","2,3,4"]
(1 OR 2) OR (3 OR 4) => ["1","2","3","4"]
我尝试过以下方法是否有比这更好的方法。
static void Main(string[] args)
{
string input = "4 AND (1 OR (2 AND 3))";
List<string> output = new List<string>();
string inputTmp = input.Replace("(", "")
.Replace(")", "")
.Replace(" AND ", ",");
if (inputTmp.Contains("OR"))
{
List<string> orOutput = new List<string>();
List<List<string>> cmbOutput = new List<List<string>>();
char splitChar = ' ';
if (input.Contains(")) AND ((")) { inputTmp = input.Replace(")) AND ((", "&"); splitChar = '&'; }
else { if (input.Contains(")) AND ")) { inputTmp = input.Replace(")) AND ", "&"); splitChar = '&'; } }
if (input.Contains(")) OR ((")) { inputTmp = input.Replace(")) OR ((", "|"); splitChar = '|'; }
else { if (input.Contains(")) OR ")) { inputTmp = input.Replace(")) OR ", "|"); splitChar = '|'; } }
if (splitChar != ' ')
{
foreach (var item in inputTmp.Split(splitChar))
{
orOutput.Add(item.Replace("(", "").Replace(")", "").Replace(" AND ", ","));
}
}
else
{
orOutput.Add(input.Replace("(", "").Replace(")", "").Replace(" AND ", ","));
}
foreach (var item in orOutput)
{
List<string> lcOutput = new List<string>();
foreach (var oritem in item.Replace(" OR ", "|").Split('|'))
{
lcOutput.Add(oritem);
}
cmbOutput.Add(lcOutput);
}
if (cmbOutput.Count > 1 && splitChar == '&')
{
for (int i = 0; i < cmbOutput[0].Count; i++)
{
for (int j = 0; j < cmbOutput[1].Count; j++)
{
output.Add(cmbOutput[0][i] + "," + cmbOutput[1][j]);
}
}
}
else
{
foreach (var item in cmbOutput)
{
foreach (var initem in item) { output.Add(initem); }
}
}
}
else
{
output.Add(inputTmp);
}
output.ForEach(o => { Console.WriteLine(o); });
Console.ReadLine();
}
答案 0 :(得分:3)
我已经创建了一种方法,希望能满足您的需求。它递归地解析给定的表达式。
源代码
public static string Parse(string s)
{
return '"' + InnerParse(s).Replace(";", "\",\"") + '"';
}
private static string InnerParse(string s)
{
int pos;
while ((pos = s.IndexOf('(')) != -1)
{
int count = 1;
int nextPos = pos;
while (count != 0)
{
nextPos = s.IndexOfAny(new[] { ')', '(' }, nextPos + 1);
if (nextPos == -1 || nextPos >= s.Length)
throw new ApplicationException(); // Unpaired parentheses
count = s[nextPos] == '(' ? count + 1 : count - 1;
}
s = (pos != 0 ? s.Substring(0, pos - 1) : String.Empty)
+ InnerParse(s.Substring(pos + 1, nextPos - pos - 1)) // Recursion
+ s.Substring(nextPos + 1);
}
string[] operands = s.Split(new[] { "AND", "OR" }, StringSplitOptions.None);
if (operands.Length != 2)
throw new ApplicationException(); // Count of operands != 2
string op1 = operands[0].Trim();
string op2 = operands[1].Trim();
// If operator is OR
if (s.Contains("OR"))
return op1 + ';' + op2;
// If operator is AND
string[] op1s = op1.Split(';');
string[] op2s = op2.Split(';');
string[] ret = new string[op1s.Length * op2s.Length];
int i = 0;
foreach (string s1 in op1s)
foreach (string s2 in op2s)
ret[i++] = s1 + ',' + s2;
return String.Join(";", ret);
}
使用示例
Console.WriteLine(Parse("(1 OR (2 AND 3)) AND 4"));
<强>限制强>
AND
,OR
。"
或分号;
。