Question

我想检查自动复选框，我尝试使用下面的代码但不检查复选框

HTML

<?php
$dbHost = 'localhost'; // usually localhost
$dbUsername = 'xxxx';
$dbPassword = 'xxxxxxxxxxx';
$dbDatabase = 'xxxxxxxxxx';
$db = mysql_connect($dbHost, $dbUsername, $dbPassword) or die ("Unable to connect to Database Server.");
mysql_select_db ($dbDatabase, $db) or die ("Could not select database.");





$variable=$_POST['chk1'];
//print $variable;
$checkbox=implode(',',$variable);

//print $checkbox;


$sql_selectcpnn="SELECT * from clientnetworkpricehistory where id in ($checkbox)";
$querycpnn = mysql_query($sql_selectcpnn);

//print$sql_selectcpnn;



echo "<table style='margin:0px;width:364px'>
<tr>

<th>DateTime</th>
<th>By(employee)</th>

</tr>";

while($row = mysql_fetch_array($querycpnn))
{ 
    $clientid=$row['clientid'];
    //print$clientid;
    $net=$row['net_id'];
    //print$net;
   $id=$row['id'];
  // print$id;

echo "<tr>";

echo "<td>" .date('d.m.Y H:i', $row['datetime']) . "</td>";
echo "<td>" . $row['user'] . "</td>";
echo"<input type='checkbox' name='chk1[]' value= '$id' checked='checked'/>";

echo "</tr>";
}
echo "</table>";

?>

任何人都可以告诉我，我的代码是什么，以显示复选框为selected.thanks

Answer 1

尝试 -

  echo "<input  type='checkbox' name='chk1[]' checked='checked' value= '$id' />";

如何自动选中复选框？

1 个答案: