Question

如果try块中的任何内容都失败，我需要回滚事务并向客户端发送正确的响应，所以我这样做：

try {
    $wf = $this->createWordForm($requestParams);
    $wfl = $this->createWordFormLink($requestParams, $wf);
    $wordList = $this->bindWordFormOrLinkToTextWord($requestParams, $wf, $wfl);
    $db->commit();
} catch (Kohana_ORM_Validation_Exception $e) {
    $exceptionHasOccured = TRUE;
    return JsonResponse::ValidationFail($this->response, $e->errors());
} catch (Exception $e) {
    $exceptionHasOccured = TRUE;
    return JsonResponse::Error($this->response, $e->getMessage());
} finally {
    if ($exceptionHasOccured) {
        $db->rollback();
    }
}

正如您所看到的，我正在使用最终构建来回滚事务。这是正确的做法吗？

Answer 1

您可以捕获一个catch块中的所有异常，只要您没有专门为任何目的使用异常类型。

try {
    $wf = $this->createWordForm($requestParams);
    $wfl = $this->createWordFormLink($requestParams, $wf);
    $wordList = $this->bindWordFormOrLinkToTextWord($requestParams, $wf, $wfl);
    $db->commit();
} catch (Exception $e) {
    $db->rollback();
    if($e instanceof Kohana_ORM_Validation_Exception ) { 
       return JsonResponse::ValidationFail($this->response, $e->errors());
    } else {
       return JsonResponse::Error($this->response, $e->getMessage())
    }
}

只有在发生异常但是多个catch子句到位时才执行语句

1 个答案: