Question

我正在解析电子邮件主题以获取特定信息。下面的函数将返回2个字符串之间存在的任何字符串。

<?php

function find_string_between_characters($haystack, $starter, $ender) {
  if(empty($haystack)) return '';
  $il = strpos($haystack,$starter,0)+strlen($starter);
  $ir = strpos($haystack,$ender,$il);
  return substr($haystack,$il,($ir-$il));
}

$string = 'Re: [Ticket #6588] Site security update';
$begin = '[Ticket #';
$end = ']';
echo find_string_between_characters($string, $begin, $end); // result: 6588
?>

结果： 6588 当然，这正是我想要的。我几乎没有注意到，如果我改变这样的变量：

<?php
$string = 'New Ticket Email Submitted';
$begin = '[Ticket #';
$end = ']';
echo find_string_between_characters($string, $begin, $end); // result: t Email
?>

结果： t电子邮件

如何调整功能以查看 $ begin 和 $ end 变量中的确切字符序列？

Answer 1

$string = 'Re: [Ticket #6588] Site security update';
preg_match('/\[Ticket #(.*?)\]/', $string, $matches);
print_r($matches);

Answer 2

您可以将preg_match用作

$input_line = 'Re: [Ticket #6588] Site security update' ;
preg_match("/\[Ticket #(.*?)\]/i", $input_line, $output_array);

echo $output_array[1];


/\[Ticket #(.*?)\]/i

    \[ matches the character [ literally
    Ticket # matches the characters Ticket # literally (case insensitive)
    1st Capturing group (.*?)
        .*? matches any character (except newline)
            Quantifier: Between zero and unlimited times, as few times as possible, expanding as needed [lazy]
    \] matches the character ] literally
    i modifier: insensitive. Case insensitive match (ignores case of [a-zA-Z])

查找2个字符串之间的字符串

2 个答案: