我正在使用json.net来序列化/反序列化字典。问题是在反序列化时,一些对象被重新创建为null。只有在使用PreserveReferenceHandling时才会发生这种情况。代码:
Dictionary<string, object> data = new Dictionary<string, object>();
data["Roles"] = (from r in Roles
select new { Id = r.Id, Name = r.Name }).ToList();
data["CompanyCourses"] = (from cvc in CompanyVideoCourses
where cvc.Company.Id == location.Company.Id
select cvc).ToList();
data["VideoCourses"] = (from vc in VideoCourses
select vc).ToList();
data["CompanyCourses"] = (from cvc in CompanyVideoCourses
where cvc.Company.Id == location.Company.Id
select cvc).ToList();
data["Location"] = location;
string output = JsonConvert.SerializeObject(data, Formatting.Indented, new JsonSerializerSettings { PreserveReferencesHandling = PreserveReferencesHandling.Objects});
Dictionary<string, object> newdata = new Dictionary<string, object>();
newdata = JsonConvert.DeserializeObject<Dictionary<string, object>>(output,
new JsonSerializerSettings { PreserveReferencesHandling = PreserveReferencesHandling.Objects });
JArray roles = JsonConvert.DeserializeObject<dynamic>(newdata["Roles"].ToString());
//problem 1 here
List<VideoCourse> videoCourses = JsonConvert.DeserializeObject<List<VideoCourse>>(newdata["VideoCourses"].ToString());
//problem 2 here
List<CompanyVideoCourse> companyCourses = JsonConvert.DeserializeObject<List<CompanyVideoCourse>>(newdata["CompanyCourses"].ToString());
Location location1 = JsonConvert.DeserializeObject<Location>(newdata["Location"].ToString());
问题变体1 - 系统具有视频课程。每个公司都可以分配多个课程。在这个测试中,有一半的可用课程被分配给公司。对视频课程进行反序列化时,任何不分配给公司的课程都为空。
问题变量2 - 如果我通过将行data["CompanyCourses"] =
放在行data["VideoCourses"] =
之后更改字典创建的顺序,那么当执行List<CompanyVideoCourse> companyCourses = ...
时,VideoCourse属性为null(这是带有附加数据的连接表。)
问题变体1和2取决于字典的顺序。如果一个发生,另一个不发生。
我已经检查了生成的json,并且所有$ id和$ ref值看起来都很好。如上所述,如果使用PreserveReferencesHandling,这只是一个问题。如果没有使用它,那么一切都按预期工作,无论字典的创建顺序如何。
所以问题是:如何重新创建所有对象?
以下是显示问题的生成json的示例。
{
"$id": "1",
"CompanyCourses": [
{
"$id": "2",
"Company": {
"$id": "3",
"Id": 1,
"Name": "Company0",
"Address": "123 e main",
"ContactName": "Joe Contact",
"ContactPhone": "2065551212",
"ContactEmail": "joec@contactcompany.com",
"Maritime_Id": "19360"
},
"VideoCourse": {
"$id": "4",
"InternetLocation": "5QyZRnYt",
"SKU": "DVD0-18",
"FileName": "Access-Control.mp4",
"CoverFileName": "Access-Control-Cover.png",
"PosterFileName": "Access-Control-Poster.png",
"VTTFileName": "Access-Control.vtt",
"RunningTime": "00:14:00",
"Id": 11,
"Name": "Access Control: Threat Awareness and Prevention",
"Description": "<p>Understand and prevent the threat of unauthorized access to your ship.</p>\r\n <p>Topics:</p>\r\n <ul>\r\n <li>Risk recognition</li>\r\n <li>Piracy and hijacking prevention</li>\r\n <li>The threat of unauthorized access</li>\r\n <li>Security and team-effort approach</li>\r\n <li>Controlling shipboard access in port</li>\r\n </ul>",
"Repeating": false,
"Interval": 0,
"Keywords": "ISPS"
},
"Id": 1,
"Corporate_Id": null
}
],
"Location": {
"$id": "14",
"Id": 1,
"Name": "ShipatSea Location0",
"Address": null,
"Company": {
"$ref": "3"
}
}
}
当反序列化时,“Location”对象中的“Company”属性为null,即使$ id $ ref指向(“3”)位于顶部。
答案 0 :(得分:0)
在序列化整个字典之前,解决方案结果是序列化字典的每个部分。这样,当每个字典值被反序列化时,它具有它自己需要的所有信息。所以,例如,这个:
data["Location"] = location;
变为
data["Location"] = JsonConvert.SerializeObject(location, new JsonSerializerSettings {
PreserveReferencesHandling = PreserveReferencesHandling.Objects
});