Question

我有这个JSON文件：

{
    "CARD_MODEL_TITLE": "OWNER'S MANUAL",
    "CARD_MODEL_SUBTITLE": "Configure your download",
    "CARD_MODEL_SELECT": "Select Model",
    "CARD_LANG_TITLE": "Select Language",
    "CARD_LANG_DEVICE_LANG": "Your device",
    "CARD_YEAR_TITLE": "Select Model Year",
    "CARD_YEAR_LATEST": "(Latest)",
    "STEPS_MODEL": "Model",
    "STEPS_LANGUAGE": "Language",
    "STEPS_YEAR": "Model Year",
    "BUTTON_BACK": "Back",
    "BUTTON_NEXT": "Next",
    "BUTTON_CLOSE": "Close"
}

我用它来将它转换为Powershell中的JSON对象的语法是这样的：

$json = (Get-Content "jsonfile.json") -join "`n" | ConvertFrom-Json

问题是我想编辑每对名称/值的值，但名称字段可能会因其他文件而异，因为我希望每个文件都有一个脚本，所以这必须是通用的。

如何在不事先知道名称字段的情况下获取对名称/值的名称字段？或者换句话说，我想要一种：foreach ($i in $json)

由于

Answer 1

您可以在转换后使用$ json.psobject.properties.name：

@'
   {
    "CARD_MODEL_TITLE": "OWNER'S MANUAL",
    "CARD_MODEL_SUBTITLE": "Configure your download",
    "CARD_MODEL_SELECT": "Select Model",
    "CARD_LANG_TITLE": "Select Language",
    "CARD_LANG_DEVICE_LANG": "Your device",
    "CARD_YEAR_TITLE": "Select Model Year",
    "CARD_YEAR_LATEST": "(Latest)",
    "STEPS_MODEL": "Model",
    "STEPS_LANGUAGE": "Language",
    "STEPS_YEAR": "Model Year",
    "BUTTON_BACK": "Back",
    "BUTTON_NEXT": "Next",
    "BUTTON_CLOSE": "Close"
   }
'@ | set-content jsonfile.json

$json = (Get-Content "jsonfile.json" -Raw) | ConvertFrom-Json

$json.psobject.properties.name

CARD_MODEL_TITLE
CARD_MODEL_SUBTITLE
CARD_MODEL_SELECT
CARD_LANG_TITLE
CARD_LANG_DEVICE_LANG
CARD_YEAR_TITLE
CARD_YEAR_LATEST
STEPS_MODEL
STEPS_LANGUAGE
STEPS_YEAR
BUTTON_BACK
BUTTON_NEXT
BUTTON_CLOSE

您还可以使用-join开关-Raw来消除Get-Content

如果您不知道，如何在Powershell中获取JSON对象的名称字段？

1 个答案: