Question

我有一个Android应用程序，它使一个post函数将数据发送到Symfony项目。然后我想在我的bd中获取这些数据和存储。我认为问题出在我的PHP代码中而不是在android的代码中。我已经尝试了很多方法，但没有结果。

我的机器人的帖子功能：

public String sendPost(String username, String password, String email, String city) {

    HttpClient httpClient = new DefaultHttpClient();
    HttpContext localContext = new BasicHttpContext();
    HttpPost httpPost = new HttpPost("https://192.168.1.120/TortillatorAPI/web/new_user");
    HttpResponse response = null;
    try 
    {   
       List<NameValuePair> params = new ArrayList<NameValuePair>(4);
       params.add(new BasicNameValuePair("username", username));
       params.add(new BasicNameValuePair("password", password));
       params.add(new BasicNameValuePair("email", email));
       params.add(new BasicNameValuePair("city", city));
       httpPost.setEntity(new UrlEncodedFormEntity(params));
       response = httpClient.execute(httpPost, localContext);
    } 
    catch (Exception e) 
    {

    }
    return response.toString();
}

新用户的路由：

new_user:
    pattern: /new_user
    defaults: { _controller:TortillatorAPITortillatorBundle:Default:newUser}

我的Symfony功能在我的控制器中：

public function newUserAction()
{
    $request = $this->getRequest();
    $user = new User();
    $user->setUsername($request->get('username'));
    $user->setPassword($request->get('password'));
    $user->setEmail($request->get('email'));
    $user->setCity($request->get('city'));

    $em = $this->getDoctrine()->getManager();
    $em->persist($user);
    $em->flush();

    $response = new Response();
    $response->setStatusCode(201);
    return $response;
}

Answer 1

我看到的一些错误，对于评论来说太大了：

更改此部分：

我的Symfony功能在我的控制器中：

public function newUserAction()
{
    $request = $this->getRequest();
    $user = new User();
    $user->setUsername($request->get('username'));
    $user->setPassword($request->get('password'));
    $user->setEmail($request->get('email'));
    $user->setCity($request->get('city'));

    $em = $this->getDoctrine()->getManager();
    $em->persist($user);
    $em->flush();

    $response = new Response();
    $response->setStatusCode(201);
    return $response;
}

如果您使用注释，否则您必须以不同方式指定路由和方法，以及我已更改了请求对象。

/**
*@Route("YOURROUTE", name="YOURROUTE")
*@Method("POST")
*@Template()
*/
public function newUserAction(Request $request)
{
    $user = new User();
    $user->setUsername($request->get('username'));
    $user->setPassword($request->get('password'));
    $user->setEmail($request->get('email'));
    $user->setCity($request->get('city'));

    $em = $this->getDoctrine()->getManager();
    $em->persist($user);
    $em->flush();

    $response = new Response();
    $response->setStatusCode(201);
    return $response;
}

如何从android的post方法获取Symfony2中的数据

1 个答案: