Question

我一直在开发一个需要Instagram Feed的网站。不幸的是，我无法让它工作！这就是我所做的。

<script type="text/javascript">
    feed = new Instafeed({
    clientId: '99808b1edfc140eda1cfa2dca4b4fe4c',
    accessToken: '201047212.467ede5.1072e8c882e34a8fb7975f725e7b3ba8',
    get: 'user',
    userId: 201047212,
    resolution: 'standard_resolution',
    links: 'false',
    template: '<div id="instafeed-caption">{{caption}} <br>&hearts; {{likes}} on <a href="{{link}}" class="sky">instagram</a></div><div id="instafeed-container"><img src="{{image}}" /></div>',
    mock: true,
    custom: {
    images: [],
    currentImage: 0,
    showImage: function () {
    var result, image;
    image = this.options.custom.images[this.options.custom.currentImage];
    result = this._makeTemplate(this.options.template, {
    model: image,
    id: image.id,
    link: image.link,
    image: image.images[this.options.resolution].url,
    caption: this._getObjectProperty(image, 'caption.text'),
    likes: image.likes.count,
    comments: image.comments.count,
    location: this._getObjectProperty(image, 'location.name')
  });
  (function($){ 
    $("#instafeed").html(result)
  })
}
  },
  success: function (data) {
    this.options.custom.images = data.data; 
    this.options.custom.showImage.call(this);
  }
});
feed.run();

(function($){
  $(".instafeed-next").click(function () {
    var length, current;
    current = feed.options.custom.currentImage;
    length = feed.options.custom.images.length;
if (current < length - 1) {
  feed.options.custom.currentImage++;
  feed.options.custom.showImage.call(feed);
}
  })
});

(function($){
  $(".instafeed-prev").click(function () {
    var length, current;
    current = feed.options.custom.currentImage;
    length = feed.options.custom.images.length;
    if (current > 0) {
      feed.options.custom.currentImage--
      feed.options.custom.showImage.call(feed);
    }
  })
});
</script>

如果有人能告诉我脚本有什么问题，我会很感激。我在Instafeed网站上举了一个例子。作为参考，该网站为www.hemeon.com。我的网站是www.vcluxe.nu/contact-me。谢谢！

Answer 1

噢，嘿..我不知道你所拥有的所有代码......但是那些不安全的页面似乎没有提到...是添加一个＆＃34;限制＆＃34; .. .this告诉instagram要放入多少图像..否则我认为默认值为零......

我做了我的：限制：＆＃39; 4＆＃39;

将非常有用的信息放入说明中！

见下文：

 <script type="text/javascript">
    var feed = new Instafeed({
        get: 'tagged',
        tagName: 'cool',
        clientId: '916c01b8624d43c7b4b76369aruc86a0',
        limit: '4' 
    });
    feed.run(); </script>

Instafeed脚本不起作用

1 个答案: