Question

我有XML文档：

<?xml version="1.0" encoding="utf-8" ?>
<Menu>
  <MainMenu>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
  </MainMenu>
</Menu>

我想把它反序列化为课程MainMenu中的列表：

   [Serializable()]
    public class MainMenu
    {
        [System.Xml.Serialization.XmlElementAttribute("Meal")]
        private List<string> Meal;

        public MainMenu()
        {
            Meal = new List<string>();
        }
    }

按方法：

private void MenuDeserializer()
{
    MainMenu mainMenu = null;
    string path = "MenuXML.xml";

    XmlSerializer serializer = new XmlSerializer(typeof(MainMenu));

    StreamReader reader = new StreamReader(path);
    reader.ReadToEnd();
    mainMenu = (MainMenu)serializer.Deserialize(reader);
    reader.Close();
}

这会将所有膳食反序列化到我的列表中吗？如果不是如何做到这一点？当我尝试调试时，我得到异常：XML文件（0,0）出错，这个（0,0）令人困惑，问题出在哪里以及如何解决？

Answer 1

1 - 删除reader.ReadToEnd（），你从一开始就移动流，所以当你反序列化时，它会尝试从文件的末尾开始。

2 - 你需要从XML中删除外部Menu元素，你的类从MainMenu开始，所以你的xml也应该......

<?xml version="1.0" encoding="utf-8" ?>
<MainMenu>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
</MainMenu>

Answer 2

如果这是你的XML：

<?xml version="1.0" encoding="utf-8" ?>
<Menu>
  <MainMenu>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
    <Meal>Example1</Meal>
  </MainMenu>
</Menu>

我想把它反序列化为MainMenu类中的列表：

   public class Menu
   {
      public MainMenu MainMenu{get;set;}
   }
    public class MainMenu
    {

        public List<string> Meal {get; set;}

        public MainMenu()
        {
            Meal = new List<string>();
        }
    }

按方法：

private void MenuDeserializer()
{
    Menu menu;
    string path = "MenuXML.xml";

    XmlSerializer serializer = new XmlSerializer(typeof(Menu));

    using(StreamReader reader = new StreamReader(path))
    {
        menu = (Menu)serializer.Deserialize(reader);
    }
}

这就是它的糟糕......

Answer 3

您显示的XML可以反序列化：

  [Serializable()]
  [System.Xml.Serialization.XmlRoot("Menu")]
  public class Menu
  {
     [XmlArray("MainMenu")]
     [XmlArrayItem("Meal", typeof(string))]
     public string[] MainMenu { get; set; }
  }

  public static void Main(string[] args)
  {
     XmlSerializer serializer = new XmlSerializer(typeof(Menu));

     using(StreamReader reader = new StreamReader("MenuXML.xml"))
     {
        Menu menu = (Menu)serializer.Deserialize(reader);
        reader.Close();
     }
  }

XML文档包含错误（0,0）

3 个答案: