Question

我有两个功能：

char* odwroc(char* nap, int n) 
char* male(char* nap, int n)

我已经定义了一个指向那种函数的指针

 typedef char*(*pointerToFunction )( char*, int );

然后在main中使用了这个定义：

 pointerToFunction ptr1 = odwroc;
 pointerToFunction ptr2 = male;

但是现在我必须创建一个函数，作为第一个参数获取指向函数的数组的数组，我被卡住了。我不知道如何定义函数指针数组以及modyfikuj参数列表的外观。

void modyfikuj(char* pointerToFunction *pointerArray, int length, char* nap2, int n){ 
}

Answer 1

试试这个：

pointerToFunction mojefunkcje[] = { odwroc, male};

modyfikuj( mojefunkcje, ...);      // pass the array fo modyfikuj()

void modyfikuj( pointerToFunction* funtab, ...)
{
    funtab[0]( string, liczba);    // call  odwroc( string, liczba)
    funtab[1]( string, liczba);    // call  male( string, liczba)
}

Answer 2

即使上面的答案有意义，使用诸如std :: vector之类的容器会在传递类似类型的数组（如指向函数的指针）时提供更多控制。请尝试以下代码段。

#include "vector"
using namespace std;

typedef char*(*pointerToFunction )( char*, int );

typedef vector<pointerToFunction> FUNCTION_VECTOR;

bool modyfikuj( FUNCTION_VECTOR& vecFunctionVector )
{
    // The below checking ensures the vector does contain at least one function pointer to be called.
    if( vecFunctionVector.size() <= 0 )
    {
        return false;
    }

    // You can have any number of function pointers to be passed and get it executed, one by one.
    FUNCTION_VECTOR::iterator itrFunction = vecFunctionVector.begin();
    FUNCTION_VECTOR::const_iterator itrFunEnd = vecFunctionVector.end();
    char* cszResult = 0;
    for( ; itrFunEnd != itrFunction; ++itrFunction )
    {
        cszResult = 0;
        // Here goes the function call!
        cszResult = (*itrFunEnd)( "Hello", 1 );

        // Check cszResult for any result.
    }

    return true;

}

char* odwroc(char* nap, int n); // You will define this function somewhere else.
char* male(char* nap, int n); // You will define this function somewhere else.

int main()
{
    FUNCTION_VECTOR vecFunctions;
    // You can push as many function pointers as you wish.
    vecFunctions.push_back( odwroc );
    vecFunctions.push_back( male );
    modyfikuj( vecFunctions );
    return  0;
}

如何将函数指针数组传递给另一个函数

2 个答案: