假设我有这样的架构。
现在我想要查阅至少有五本书结账的借款人的姓名,地址和结账数量。
过了一段时间,我提出了这个解决方案,因为我在数据库中更新鲜:
SELECT BR.Name, BR.Address,
Checkout.NoOfBookCheckedOut
FROM Borrower BR, (
SELECT CardNo, COUNT(BookId) AS 'NoOfBookCheckedOut'
FROM Book_Loans
WHERE DateOut IS NOT NULL
GROUP BY CardNo
HAVING COUNT(BookId) >= 5
) AS 'Checkout'
WHERE Checkout.CardNo = BR.CardNo
我的解决方案是否正确?有没有更好的方法来优化此查询?
答案 0 :(得分:2)
您可以在此处使用内部联接
SELECT BR.Name, BR.Address,
Checkout.NoOfBookCheckedOut
FROM Borrower BR
INNER JOIN (
SELECT CardNo, COUNT(BookId) AS 'NoOfBookCheckedOut'
FROM Book_Loans
WHERE DateOut IS NOT NULL
GROUP BY CardNo
HAVING COUNT(BookId) >= 5
) Checkout
ON Checkout.CardNo = BR.CardNo
答案 1 :(得分:1)
我认为您可以通过连接两个表来简化查询,而无需派生表。
SELECT
BR.Name,
BR.Address,
COUNT(BL.BookId) as NoOfBookCheckedOut
FROM
Borrower BR JOIN Book_Loans BL ON BR.CardNo = BL.CardNo
WHERE
BL.DateOut IS NOT NULL
GROUP BY
BR.Name,
BR.Address
HAVING
COUNT(BL.BookId) >= 5
答案 2 :(得分:0)
要优化查询,请确保在join和where子句中使用的列上有适当的索引。