Question

我打算成为可能的是

如果我是用户，我的左，右是“L”和“R”

我想php应该自动chk可能的空位注册。像

1 = L，2 = R，3 = LL，4 = RL，5 = LR，6 = RR

       user
       / \
  (1) L   R (2)
     /\   /\
(3) LL LR RL RR (6)
      (5) (4)

如果发现“RL”位置为空（新用户应在“RL”下注册）

我的数据库有ID，用户名，Child_L，Child_R

我在这里编写了以下代码

<?php

require_once 'config.php';
$username = "kishore";
$log=mysql_query("select * from users where username='".$username."'");
$row=mysql_fetch_array($log);

$child_left=$row['child_l'];
$child_left=$row['child_r'];

function chkchild($childuser){
    $log=mysql_query("select * from users where username='".$childuser."'");
    $row=mysql_fetch_array($log);

    $child_left=$row['child_l'];
    $child_left=$row['child_r'];

    if ($child_left = NULL) {

        echo"you can register under child_l";
    }elseif ($child_right = NULL){
        echo"you can register under child_r";
    }

}


if ($child_left = NULL) {

    echo"you can register under child_l";
}elseif ($child_right = NULL){
    echo"you can register under child_r";
}else 
    chkchild($child_left);


?>

这是我的数据库表

http://i.imgur.com/nuWv7vT.jpg

Answer 1

可能会帮助你

function chkchild(){
    while($t)
    {
        $qu=mysql_query("SELECT * FROM users WHERE child_L='' or child_R='';");
        $rows=mysql_fetch_row($qu);
        if($rows>0)
        {
            echo "No Positions are blank"
        }
        else
        {
            $rs=mysql_fetch_array($qu);
            //Here you can check the complete list of all blank positions
        }
    }
}

自动检查PHP中的可用性位置 - MLM项目

1 个答案: