作为一名初学者,我从过去的代码审查中获得了一些知识,我尝试进行代码审查,但不知何故让程序停止按预期工作。假设在5场比赛后打破循环,有时只会这样做。
import random
import math
import console
console.set_font('Arial-BoldMT',15)
print'Welcome to the guessing game!\nA number will be randomly chosen from 0 to 1000.\nThe player will make a guess, and then the computer will guess. Who ever is closest wins that round!\nFirst to 5 wins!'
rounds = 0
run_again = 'y'
player_wins = 0
computer_wins = 0
draws = 0
while run_again == 'y':
number = random.randint(0,1000)
player_number = input('\nPlayer: ')
computer_number = random.randint(0,1000)
print 'Computer:', computer_number
print 'Number:', number
player_score=math.fabs(player_number-number)
computer_score=math.fabs(computer_number-number)
if player_score>=computer_score:
computer_wins+=1
rounds +=1
console.set_color(1.00, 0.00, 0.00)
print 'You lost that round'
console.set_color(0.00, 0.00, 0.00)
if player_score<=computer_score:
player_wins+=1
rounds +=1
console.set_color(0.00, 0.00, 1.00)
print 'You won that round'
console.set_color(0.00, 0.00, 0.00)
if player_score==computer_score:
draws+=1
rounds +=1
console.set_color(0.00, 1.00, 0.00)
print 'That round was a tie'
console.set_color(0.00, 0.00, 0.00)
if rounds == 5:
if player_wins == 4:
console.set_color(0.00, 0.00, 1.00)
print '\nYOU WON THE GAME'
console.set_color(0.00, 0.00, 0.00)
break
if computer_wins == 4:
console.set_color(1.00, 0.00, 0.00)
print '\nYOU LOST THE GAME'
console.set_color(0.00, 0.00, 0.00)
break
答案 0 :(得分:2)
我认为如果你正确地考虑了结果,那就没关系了:
if rounds == 5:
if playr_wins > computer_wins:
console.set_color(0.00, 0.00, 1.00)
print '\nYOU WON THE GAME'
console.set_color(0.00, 0.00, 0.00)
break
elif computer_wins > playr_wins:
console.set_color(1.00, 0.00, 0.00)
print '\nYOU LOST THE GAME'
console.set_color(0.00, 0.00, 0.00)
break
else:
print "Wrong counts"
答案 1 :(得分:1)
如果一名球员或另一名球员获得4胜,则只有break
。使用for
循环来限制轮次要容易得多:
for _ in range(5):