Question

这是一个小问题，但我花了好几个小时试图弄清楚它为什么不起作用。

我正在尝试使用以下代码从mysql数据库中获取firstname或lastname：

<?php
 include "config/connect.php";

 $manager = 'myemail@yahoo.co.uk';

    $stmt = mysqli_prepare(
    $db_conx,
    "SELECT  lastname
     FROM members
     WHERE email = ?
     AND lastname = ?");
//after validation, of course
mysqli_stmt_bind_param($stmt, "ss", $manager, $lastname);
mysqli_stmt_execute($stmt);
print $lastname;
if (mysqli_affected_rows($db_conx))
{
    mysqli_stmt_close($stmt);//<-- CLEAN UP AFTER YOURSELF!
    $id = mysqli_insert_id($db_conx);


}
?>

出于某种奇怪的原因，它根本不打印lastname或lastname。但如果我打印manager，它会正确打印出来。

我做错了什么？

P.S。我知道数据库中存在email，firstname和lastname。

编辑：

 include "config/connect.php";

 $manager = 'MYEMAIL@yahoo.co.uk';


$stmt = $db_conx->prepare("SELECT  email, firstname
     FROM members
     WHERE email = ?
       AND firstname = ?");
    $stmt->bind_param('ss', $manager, $firstname);
    $stmt->execute();
    $stmt->bind_result($manager, $firstname);
    $stmt->store_result();
    if($stmt->num_rows == 1)  //To check if the row exists
        {
            while($stmt->fetch()) //fetching the contents of the row

              { 
         $firstname = $firstname;
         $manager = $manager;


              }
        }
        $stmt->close();

Answer 1

我不明白，你想做什么，

如果你想获得FIRSTNAME和LASTNAME

$stmt = mysqli_prepare($db_conx,"SELECT  firstname,lastname FROM members WHERE email = ?");
$stmt->bind_param('s', $manager);

 $stmt->execute();
$stmt->bind_result($fname, $lname);

/* fetch values */

while ($stmt->fetch()) {
    printf("%s %s\n", $fname, $lname);
}

使用mysqli编写的mysql数据库获取名字和姓氏？

1 个答案: