Question

我正在为我的SQLite数据库创建AUTOINCREMENT函数，但每当我输入AUTOINCREMENT函数时，我都会收到错误＆＃39; SYNTAX＆＃39;错误，我做错了什么？

<?php
$db = sqlite_open("user_indormation.db");

@sqlite_query($db, "DROP TABLE user_info");

sqlite_query($db,
"CREATE TABLE user_info (
 ID                     INTEGER(100) AUTOINCREMENT,
 FirstName              VARCHAR2(10) NOT NULL,
 SurName                VARCHAR2(10) NOT NULL,
 UserName               VARCHAR2(10) NOT NULL,
 CONSTRAINT USER_PRIMARY_KEY PRIMARY KEY (FirstName));
INSERT INTO 'user_info' VALUES('kim','lim','jim');
INSERT INTO 'user_info' VALUES('tom','tim','zim')"
,$sqliteerror);

$result=sqlite_query($db,"SELECT * from user_info");
echo "<table border=1>";

while($row=sqlite_fetch_array($result,SQLITE_NUM ))
{
    echo "<tr>";
    for ($i = 0; $i < sizeof($row)  ; $i++) {
     echo "<td>" . $row[$i] . "</td>"; 
   }
   echo "</tr>";
}
echo "</table>";

sqlite_close($db);
?>

Answer 1

我想要弄明白，只需改变：

ID                     INTEGER(100) AUTOINCREMENT,

到

ID                     INTEGER PRIMARY KEY,

并为主键插入一个值为null：

INSERT INTO 'user_info' VALUES(NULL,'tom','bob','zim');

或

INSERT INTO user_info (ID,FirstName,Surname,UserName) VALUES(NULL,'tom','bob','zim');

了解更多信息https://sqlite.org/faq.html#q1

Answer 2

您只能将AUTOINCREMENT与INTEGER PRIMARY KEY一起使用。将列规格更改为

ID INTEGER PRIMARY KEY AUTOINCREMENT

PHP中的AUTOINCREMENT问题

2 个答案: