我正在使用数组将数据插入名为tPerson的表中。如果脚本成功完成了它的作用,它将回显:
SQL: INSERT INTO tPerson(Salutation,FirstName,LastName,CompanyID)价值观(Mr,Morris,Sparrow,4)(Mrs,Mary,Haslett,2)(Ms,Gill,Hennesey,1)
是成功的。
它的工作并没有成功并且回应:
SQL: INSERT INTO tPerson(Salutation,FirstName,LastName,CompanyID)价值观(Mr,Morris,Sparrow,4)(Mrs,Mary,Haslett,2)(Ms,Gill,Hennesey,1)
失败。
我的代码如下:
$hostname = "localhost";
$username = "root";
$password = "";
$databaseName = "alphacrm";
$dbConnected = @mysql_connect($hostname, $username, $password);
$dbSelected = @mysql_select_db($databaseName, $dbConnected);
$dbSuccess = true;
if ($dbConnected) {
if (!$dbSelected) {
echo "DB connection FAILED<br><br>";
$dbSuccess = false;
} else {
echo "DB connection SUCCESSFUL<br><br>";
}
} else {
echo "MySql connection FAILED<br><br>";
}
}
// Execute code ONLY if connections were successful
if ($dbSuccess) {
{ // setup ARRAY of field names
$personField = array(
"Salutation" => "Salutation",
"FirstName" => "FirstName",
"LastName" => "LastName",
"CompanyID" => "CompanyID"
);
}
{ // setup ARRAY of data ROWS
$personData[0] = array("Mr","Morris","Sparrow","4");
$personData[1] = array("Mrs","Mary","Haslett","2");
$personData[2] = array("Ms","Gill","Hennesey","1");
$numRows = sizeof($personData);
}
{ // SQL statement with ARRAYS
//Fieldnames part of INSERT statement
$person_SQLinsert = "INSERT INTO tPerson (
".$personField["Salutation"].",
".$personField["FirstName"].",
".$personField["LastName"].",
".$personField["CompanyID"]."
)";
// VALUES part of INSERT statement
$person_SQLinsert .= "VALUES ";
$indx = 0;
$person_SQLinsert .= "(
".$personData[$indx][0].",
".$personData[$indx][1].",
".$personData[$indx][2].",
".$personData[$indx][3]."
)";
$indx++;
$person_SQLinsert .= "(
".$personData[$indx][0].",
".$personData[$indx][1].",
".$personData[$indx][2].",
".$personData[$indx][3]."
)";
$indx++;
$person_SQLinsert .= "(
".$personData[$indx][0].",
".$personData[$indx][1].",
".$personData[$indx][2].",
".$personData[$indx][3]."
)";
}
{ // Echo and execute the SQL and test for success
echo "<strong><u>SQL:<br></u></strong>";
echo $person_SQLinsert."<br><br>";
if (mysql_query($person_SQLinsert)) {
echo "was SUCCESSFUL.<br<br>";
} else {
echo "FAILED.<br><br>";
}
}
} // END ($dbSuccess)
?>
所有的帮助都将受到赞赏,因为我很难理解为什么我的剧本不起作用。
答案 0 :(得分:0)
就像@mysql_select_db用于@mysql_query而不是这个mysql_query一样。 还检查了你的mysql连接和数据库连接是否成功。
您对多行的查询必须采用此格式 &#34; INSERT INTO表(Column1,Column2)VALUES(Value1,Value2),(Value1,Value2);&#34;
打印您的查询并使用此语法进行检查。