Question

$u=$_POST['userid'];

$sql=mysqli_query($con,"SELECT COUNT(username) AS total FROM TABLENAME where username=$u");

此查询仅返回username=$u

的总记录

我希望所有用户记录全部显示

我想要喜欢的东西

User           Records
User1            1152
user2            2365
user3            2365 
------            -------
userN           XXX

我正在使用php和mysql。

另请告诉我。我应该回应什么，$sql或Total？

感谢您的帮助

我试过这个：并在线接收错误：

while($fetch = mysql_fetch_assoc($sql))

这是你们给我的代码

“;的print_r（$阵列）; mysqli_close（$ CON）; ？＆GT;

再次感谢

Answer 1

尝试使用GROUP BY

$sql = mysqli_query($con,"SELECT username, COUNT(username) AS total 
                          FROM TABLENAME GROUP BY username");

$array = array();
while($fetch = mysqli_fetch_assoc($sql))
{
    $array[$fetch['username']] = $fetch['total'];
}

echo '<pre>'; print_r($array);

$array会给你你想要的东西。

Answer 2

这应该是每个用户的诀窍：

SELECT COUNT(username) AS total FROM TABLENAME GROUP BY username

Answer 3

SELECT COUNT(username) AS total FROM TABLENAME GROUP BY username

如果你想看看它是哪个用户，只需将它添加到SELECT：

SELECT username, COUNT(username) AS total FROM TABLENAME GROUP BY username

^如问题所述，应该这样做。

显示结果：

$u=$_POST['userid'];

$sql=mysqli_query($con,"SELECT COUNT(username) AS total FROM TABLENAME where username=$u");

while ($user = $sql->fetch_assoc()){
    echo($user["username"] . ": " . $user["total"]);
}

显示每个用户的记录总数

3 个答案: