好的,首先我在这里有一个数组
Dim JD = {"0", "LIE"}
然后我有3个文本框,我也放在数组
Dim ColJD1 As TextBox() = {Me.JD1_1, Me.JD1_2, Me.JD1_3}
然后我在子程序中使用这些数组:
Sub fillword(ByVal num1, ByVal qtychar, ByVal num2, ByVal i, ByVal Coltxtbox)
If Strings.Mid(My.Computer.FileSystem.ReadAllText("SAVE.txt"), Strings.InStr(My.Computer.FileSystem.ReadAllText("SAVE.txt"), num1), qtychar) = num2 & ".True" Then
For test = 1 To Strings.Len(JD(i))
For Each txtbox In Coltxtbox
Dim a As String = Strings.Mid(JD(i), test, 1)
MsgBox(a)
txtbox.Text = i => here is the problem
i = i + 1
Next
Next
End If
End Sub
Sub loadgame1()
fillword("1", 6, "1", 1, ColJD1)
End Sub
Private Sub Button_click bla bla
loadgame1()
End Sub
它的投掷错误: "对象变量或未设置块变量。"
非常感谢任何形式的帮助
@ w0051977实际上变量名是" test"而不是" uji"
收到汉斯建议后,我确实修改了代码,但仍然会抛出错误: 我改变了代码:
Dim JD = {"0", "RIA"}
Dim ColJD1 As TextBox()
Sub fillarray()
InitializeComponent()
ColJD1 = {JD1_1, JD1_2, JD1_3}
End Sub
Sub fillword(ByVal num1, ByVal qtychar, ByVal num2, ByVal i, ByVal Coltxtbox)
fillarray()
If Strings.Mid(My.Computer.FileSystem.ReadAllText("SAVE.txt"), Strings.InStr(My.Computer.FileSystem.ReadAllText("SAVE.txt"), num1), qtychar) = num2 & ".True" Then
For test = 1 To Strings.Len(JD(i))
For Each txtbox In Coltxtbox => Now the problem moves here , it throws error "Object reference not set to an instance of an object."
Dim a As String = Strings.Mid(JD(i), test, 1)
MsgBox(a)
txtbox.Text = i
i = i + 1
Next
Next
End If
End Sub
Sub loadgame1()
fillword("1", 6, "1", 1, ColJD1)
End Sub
Private Sub Button_click bla bla
loadgame1()
End Sub
答案 0 :(得分:1)
使用调试器,您可以检查变量以找到Nothing。
很可能是ColJD1
数组,无法看到调用的范围,但这是非常常见的错误。在运行InitializeComponent()方法之后,像Me.JD1_1这样的成员才会获得一个值。该变量很快就会初始化,之前该方法运行。所以它只包含Nothing元素。你需要这样写:
Dim ColJD1 As TextBox()
Public Sub New
InitializeComponent()
ColJD1 = {Me.JD1_1, Me.JD1_2, Me.JD1_3}
End Sub
Sub New是需要添加的构造函数。