Question

Iam目前正在使用PHP从MongoDB中读取数据，如下所示，我的程序中的以下PHP输出需要转换为JSON样式输出，如下所示

Mongo DB PHP输出

数组（[_id] =＆gt; MongoId对象（[$ id] =＆gt; 53481398834269e8e25fa268） [category] =＆gt; 2014-04-01 [value1] =＆gt; 400 [value2] =＆gt; 200）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 534813a9834269e8e25fa269） [category] =＆gt; 2014-04-02 [value1] =＆gt; 405 [value2] =＆gt; 205）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 534813d7834269e8e25fa26a） [category] =＆gt; 2014-04-03 [value1] =＆gt; 408 [value2] =＆gt; 211）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 534813ec834269e8e25fa26b） [category] =＆gt; 2014-04-04 [value1] =＆gt; 418 [value2] =＆gt; 198）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 53481402834269e8e25fa26c） [category] =＆gt; 2014-04-05 [value1] =＆gt; 370 [value2] =＆gt; 221）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 53481439834269e8e25fa26d） [category] =＆gt; 2014-04-06 [value1] =＆gt; 299 [value2] =＆gt; 180）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 5348144e834269e8e25fa26e） [category] =＆gt; 2014-04-07 [value1] =＆gt; 311 [value2] =＆gt; 224）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 53481461834269e8e25fa26f） [category] =＆gt; 2014-04-08 [value1] =＆gt; 315 [value2] =＆gt; 254）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 5348146f834269e8e25fa270） [category] =＆gt; 2014-04-09 [value1] =＆gt; 325 [value2] =＆gt; 264）阵列（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 5348147f834269e8e25fa271） [category] =＆gt; 2014-04-10 [value1] =＆gt; 335 [value2] =＆gt; 255）数组（ [_id] =＆gt; MongoId对象（[$ id] =＆gt; 5348148c834269e8e25fa272） [category] =＆gt; 2014-04-11 [value1] =＆gt; 365 [value2] =＆gt; 265）

JSON Style PHP Out

[{＆＃34; category＆＃34;：＆＃34; 2013-08-24＆＃34;，＆＃34; value1＆＃34;：417，＆＃34; value2＆＃34;：127}， { ＆＃34;类别＆＃34;：＆＃34; 2013-08-25＆＃34;，＆＃34; value1＆＃34;：417，＆＃34; value2＆＃34;：356}，{ ＆＃34;类别＆＃34;：＆＃34; 2013-08-26＆＃34;，＆＃34; value1＆＃34;：531，＆＃34; value2＆＃34;：585}，{ ＆＃34;类别＆＃34;：＆＃34; 2013-08-27＆＃34;，＆＃34; value1＆＃34;：333，＆＃34; value2＆＃34;：910}，{ ＆＃34;类别＆＃34;：＆＃34; 2013-08-28＆＃34;，＆＃34; value1＆＃34;：552，＆＃34; value2＆＃34;：30}，{＆＃34;类别＆＃34 ;: ＆＃34; 2013-08-29＆＃34;，＆＃34; value1＆＃34;：492，＆＃34; value2＆＃34;：371}，{＆＃34; category＆＃34;：＆＃34; 2013-08-30＆＃34;，＆＃34; value1＆＃34;：379，＆＃34; value2＆＃34;：781}，{＆＃34; category＆＃34;：＆＃34; 2013-08-31＆＃34;，＆＃34; value1＆＃34;：767，＆＃34; value2＆＃34;：494}，{＆＃34; category＆＃34;：＆＃34; 2013-09-01＆＃34;，＆＃34; value1＆＃34;：169，＆＃34; value2＆＃34;：364}，{＆＃34; category＆＃34;：＆＃34; 2013-09-02＆＃34;，＆＃34; value1＆＃34;：314，＆＃34; value2＆＃34;：476}，{＆＃34; category＆＃34;：＆＃34; 2013-09-03＆＃34;，＆＃34; value1＆＃34;：437，＆＃34; value2＆＃34;：759}]

需要专家帮助

Answer 1

在编码之前，您需要循环遍历数组并以您需要的方式重建它：

$data_to_encode = array();
foreach($mongo_objects as $mongo){
    $data['category'] = $mongo['category'];
    $data['value1'] = $mongo['value1'];
    $data['value2'] = $mongo['value2'];
    $data_to_encode[] = $data;
}

$json = json_encode($data_to_encode);

如果您想要更少的变量：

$data = array();
foreach($mongo_objects as $mongo){
    $data[] = array('category'=>$mongo['category'],
                    'value1'=>$mongo['value1'],
                    'value2'=>$mongo['value2'],
              );
}

$json = json_encode($data);

Answer 2

$json_output = json_encode($MongoDBPHPoutput, true);

MongoDB php解析为Json样式输出

2 个答案: