Question

想要调用排名位置是否可以与@curRank一起使用？

我用

创建了一个排名表

    SELECT `item`, (`totalrate` / `nrrates`) AS `rank`, @curRank := @curRank 
+ 1 AS `ranking`  FROM `rtgitems`, (SELECT 

    @curRank := 0) r WHERE item
    REGEXP 'Total'
     ORDER BY (`totalrate` / `nrrates`)  DESC

我得到一张桌子

item       rank      ranking 

Karla       9.5       1
Kelly       9.3       2
Arian       9.1429    3

在凯利页面中，我想打电话给她的排名位置

    SELECT `item`, (`totalrate` / `nrrates`) 
AS `rank`, @curRank := @curRank + 1 AS `ranking` 
FROM `rtgitems`, 
(SELECT @curRank := 0) r WHERE item REGEXP 'kelly' 
ORDER BY (`totalrate` / `nrrates`) DESC LIMIT 10
echo "<td align='center' width='250'>" . $row['ranking'] . "</td>";

但它只给我1而不是2

Answer 1

您可以将WHERE子句移出排名计算结果。

示例：

SELECT * FROM ( SELECT `item`, (`totalrate` / `nrrates`) AS `rank`, @curRank := @curRank + 1 AS `ranking` FROM `rtgitems`, (SELECT @curRank := 0) r ORDER BY (`totalrate` / `nrrates`) DESC LIMIT 10 ) results WHERE item REGEXP 'kelly'

Answer 2

您可以使用以下任何一种解决方案：

您需要使用子查询来保持排名。

这将为您提供排名为4的结果：

SELECT * 
FROM
(
    SELECT item, (`totalrate` / `nrrates`) AS `rank`,     
    @curRank := @curRank + 1 AS ranking
    FROM rtgitems p, (SELECT @curRank := 0) r 
    ORDER BY (`totalrate` / `nrrates`) DESC
) AS stat
WHERE ranking = 2;

您甚至可以使用LIMIT OFFSET来进行查询：

    SELECT item, (`totalrate` / `nrrates`) AS `rank`
    FROM rtgitems
    ORDER BY (`totalrate` / `nrrates`) DESC 
    LIMIT 4, 1

如何从@curRank获得排名位置

2 个答案: