C char无法在if..else中工作

Question

当我运行程序时，无论我为shape输入什么，都会执行最后的else语句。

#include <stdio.h>

int main(void)
{
    char shape = 'a';
    printf("What shape do you want?\nEnter 's' for a Square, 'b' for a Box, 't' for a Triangle\n");

    while (shape != 's' && shape != 'b' && shape != 't')
    {
        scanf_s(" %c", &shape);

        if (shape == 's')
        {
            printf("You entered %c", shape);
        }

        else if (shape == 'b')
        {
            printf("You entered %c", shape);
        }

        else if (shape == 't')
        {
            printf("you entered %c", shape);
        }

        else
        {
            printf("Please enter 's' 'b' or 't'");
        }
    }
    return 0;
}

Answer 1

您似乎在参数1中有空格字符。

scanf_s(" %c", &shape);

Answer 2

scanf_s需要您想要读取的字符数（因此_s）。试试scanf(" %c", &shape, 1)。

Answer 3

将scanf_s(" %c", &shape);替换为scanf_s(" %c", &shape, (size_t)1);或scanf(" %c", &shape);。 你没有提供足够的论据。