Question

我有一个充满字典的数组，每天一个。在每个字典里面我都有一个练习列表，每个练习里面都有一个带有两个值的数组。我写的程序有几个训练程序的选择器，保存为一个名为programInt的整数。我还有一个方法将这个Int转换为一个名为programPickerText的字符串。这是我到目前为止的代码：

    // create array
    self.liftData = [NSMutableArray array];

    // fill array with dictionaries, one for each day
    for (int i = 0; i < 5; i++){

        [self.liftData setObject:[NSMutableDictionary dictionary] atIndexedSubscript:i];

        // create an array for exercises
        self.liftData[i][@"Exercise1"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        self.liftData[i][@"Exercise2"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        self.liftData[i][@"Exercise3"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        self.liftData[i][@"Exercise4"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        self.liftData[i][@"Exercise5"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        self.liftData[i][@"Exercise6"] = [NSMutableArray arrayWithObjects:@"",@"", nil];

        NSLog(@"array is %@", self.liftData);
      }

我基本上需要我的可变数组（self.liftData）才能以下列格式保存信息：

self.liftData[program][day][@"Exercise1"][0]

目前它保存的数据如下：

self.liftData[Day][@"Exercise1"][0]

Answer 1

有时候实际使用命名变量非常有用

// Create an array of programs
NSMutableArray* programArray = [NSMutableArray array];
self.liftData = programArray;

for (int programIndex = 0; programIndex < ....???...) {

    // Add an array of days to the program
    NSMutableArray* dayArray = [NSMutableArray array];
    [programArray addObject:dayArray];

    // fill dayArray with dictionaries, one for each day
    for (int dayIndex = 0; dayIndex < 5; dayIndex++){

        // Add a dictionary of exercises to the day
        NSMutableDictionary* exerciseDict = [NSMutableDictionary dictionary];
        [dayArray addObject:exerciseDict];

        // Fill exerciseDict with exercises
        exerciseDict[@"Exercise1"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        exerciseDict[@"Exercise2"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        exerciseDict[@"Exercise3"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        exerciseDict[@"Exercise4"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        exerciseDict[@"Exercise5"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
        exerciseDict[@"Exercise6"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    }
}
NSLog(@"The program array is %@", self.liftData);

Answer 2

你能再添加一个NSMutableArray吗？

// create array
self.liftData = [NSMutableArray array];
NSMutableArray *programmArray = [NSMutableArray array];
[self.liftData addObject:programmArray];

// fill array with dictionaries, one for each day
for (int i = 0; i < 5; i++){

    [programmArray setObject:[NSMutableDictionary dictionary] atIndexedSubscript:i];

    // create an array for exercises
    programmArray[i][@"Exercise1"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    programmArray[i][@"Exercise2"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    programmArray[i][@"Exercise3"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    programmArray[i][@"Exercise4"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    programmArray[i][@"Exercise5"] = [NSMutableArray arrayWithObjects:@"",@"", nil];
    programmArray[i][@"Exercise6"] = [NSMutableArray arrayWithObjects:@"",@"", nil];

    NSLog(@"array is %@", self.liftData);
  }

Answer 3

我认为Avt的答案错过了一层。在回答之前，让我这样说：有时当您的数据表示变得复杂且足够深时，创建一些类并抽象出内部表示是有意义的，这样您就可以使用可读的方法名称。例如，[myProgram getExerciseArrayForDay:CONST_WEEKDAY_TUESDAY];这不仅使代码更易读，更容易实现，而且如果更改基础数据表示，代码更改也是非常本地化的。也就是说，这是一种使用大量方法来避免让自己混淆的方法。

self liftData = [NSMutableDictionary dictionary];
[self.liftData addObject:[self newProgram] forKey:@"firstProgram"];


-(NSMutableArray *) newProgram(){
    NSMutableArray *program = [NSMutableArray array];
    for(int i = 0; i < 7; i++) {
        [program addObject:[self newDayExercises]];
    }
    return program;
}

-(NSMutableDictionary *) newDayExercises {
    static NSArray *keyNames = @[@"Exercise1", @"Exercise2", @"Exercise3", @"Exercise4", @"Exercise5", @"Exercise6"];
    NSMutableDictionary *dayExercises = [NSMutableDictionary dictionary];
    for(NSString *keyName in keyNames) {
        [dayExercises addObject:@{@"", @""} forKey:keyName]; // note handy NSDictionary initializer
    }
    return dayExercises;
}

NSMutableArray中的字典

3 个答案: