Question

我知道这是一个简单的问题，但我似乎无法弄清楚我做错了什么。我应该写一个类似彩票的节目。一个数组包含5个随机数，另一个数组包含用户选择的5个数字。我使用冒泡排序来组织数字，然后尝试比较两个数组。当我运行该程序时，它总是说用户是胜利者，即使他们甚至没有得到正确的单个数字。我已尝试过循环，而循环，if / else，我不知道我哪里出错了。如果你能告诉我我哪里出错了，或者至少引导我走向正确的方向？

int main()
{
    // Variables
    int winningNumbers[5] = {};
    int numbersToPlay[5] = {};
    bool winner = true;

    std::random_device rd; // obtain a random number from hardware
    std::mt19937 eng(rd()); // seed the generator
    std::uniform_int_distribution<> distr(1, 40); // define the range

    for (int i = 0; i < 5; i++)
    {
        winningNumbers[i] = distr(eng);
    } // generate random lotto numbers

    // sort lotto numbers low to high
    bubbleSort(winningNumbers);

    // prompt user to select numbers to play
    cout << "Input 5 numbers [1-40]: ";
    for (int i = 0; i < 5; i++)
    {
        cin >> numbersToPlay[i];
    }

    // sort played numbers
    bubbleSort(numbersToPlay);

    // check for winner
    int index = 0;
    while (index < 5)
    {
        if (numbersToPlay[index] == winningNumbers[index])
        {
            winner = true;
            index++;
        }
        else
        {
            winner = false;
            break;
        }
    }

    if (winner = true)
        cout << "Winner!" << endl;
    else
        cout << "Not a winner..." << endl;

return 0;
}

Answer 1

if (winner == true) // Use `==` equality operator
{
  cout << "Winner!" << endl;

}

Answer 2

在你的代码中最后一个条件：

    if (winner = true)

将winner分配给true，您不是这样做比较：

    if(winner==true)

如何比较两个数组c ++

2 个答案: