我的代码如下:
控制器
@RequestMapping(value="/setTest", method=RequestMethod.POST, consumes="application/json")
public @ResponseBody ModelMap setTest(@RequestBody List<TestS> refunds, ModelMap map) {
for(TestS r : refunds) {
System.out.println(r.getName());
}
// other codes
}
TestS pojo
public class TestS implements Serializable {
private String name;
private String age;
//getter setter
}
Json请求
var z = '[{"name":"1","age":"2"},{"name":"1","age":"3"}]';
$.ajax({
url: "/setTest",
data: z,
type: "POST",
dataType:"json",
contentType:'application/json'
});
发出此错误
java.lang.ClassCastException:java.util.LinkedHashMap无法强制转换为com.gogoair.cidb.entities.TestS
我正在使用 spring 3.1.2 和 jackson 2.0.4
编辑:我希望在我的控制器方法中接收TestS对象列表,然后对其进行处理。我无法找到我发送错误的json或我的方法签名是错误的。
答案 0 :(得分:41)
这是适合我的代码。关键是你需要一个包装类。
public class Person {
private String name;
private Integer age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getAge() {
return age;
}
public void setAge(Integer age) {
this.age = age;
}
@Override
public String toString() {
return "Person [name=" + name + ", age=" + age + "]";
}
PersonWrapper类
public class PersonWrapper {
private List<Person> persons;
/**
* @return the persons
*/
public List<Person> getPersons() {
return persons;
}
/**
* @param persons the persons to set
*/
public void setPersons(List<Person> persons) {
this.persons = persons;
}
}
我的控制器方法
@RequestMapping(value="person", method=RequestMethod.POST,consumes="application/json",produces="application/json")
@ResponseBody
public List<String> savePerson(@RequestBody PersonWrapper wrapper) {
List<String> response = new ArrayList<String>();
for (Person person: wrapper.getPersons()){
personService.save(person);
response.add("Saved person: " + person.toString());
}
return response;
}
发送的请求是POST中的json
{"persons":[{"name":"shail1","age":"2"},{"name":"shail2","age":"3"}]}
响应是
["Saved person: Person [name=shail1, age=2]","Saved person: Person [name=shail2, age=3]"]
答案 1 :(得分:12)
这是你尝试它的方式所不可能的。杰克逊解组工作在编译的java代码之后类型擦除。所以你的
public @ResponseBody ModelMap setTest(@RequestBody List<TestS> refunds, ModelMap map)
真的只是
public @ResponseBody ModelMap setTest(@RequestBody List refunds, ModelMap map)
(列表中没有泛型arg)。
解密List
时,杰克逊创建的默认类型为LinkedHashMap
。
如@Saint所述,您可以通过为列表创建自己的类型来避免这种情况:
class TestSList extends ArrayList<TestS> { }
然后将控制器签名修改为
public @ResponseBody ModelMap setTest(@RequestBody TestSList refunds, ModelMap map) {
答案 2 :(得分:8)
asyncConnect(
someStuff,
connect(moreStuff)
)(props => <div />)
我们可以使用如上所示的Array。
答案 3 :(得分:1)
我相信这会解决问题
var z = '[{"name":"1","age":"2"},{"name":"1","age":"3"}]';
z = JSON.stringify(JSON.parse(z));
$.ajax({
url: "/setTest",
data: z,
type: "POST",
dataType:"json",
contentType:'application/json'
});
答案 4 :(得分:0)
对于我下面的代码工作,首先发送带有正确标题的json字符串
$.ajax({
type: "POST",
url : 'save',
data : JSON.stringify(valObject),
contentType:"application/json; charset=utf-8",
dataType:"json",
success : function(resp){
console.log(resp);
},
error : function(resp){
console.log(resp);
}
});
然后在Spring方面 -
@RequestMapping(value = "/save",
method = RequestMethod.POST,
consumes="application/json")
public @ResponseBody String save(@RequestBody ArrayList<KeyValue> keyValList) {
//Saving call goes here
return "";
}
这里KeyValue是简单的pojo,对应于你的JSON结构,你可以根据需要添加产生,我只是返回字符串。
我的json对象是这样的 -
[{"storedKey":"vc","storedValue":"1","clientId":"1","locationId":"1"},
{"storedKey":"vr","storedValue":"","clientId":"1","locationId":"1"}]
答案 5 :(得分:0)
解决方案效果很好
public List<String> savePerson(@RequestBody Person[] personArray)
对于此签名,您可以像
一样从邮递员传递Person
数组
[
{
"empId": "10001",
"tier": "Single",
"someting": 6,
"anything": 0,
"frequency": "Quaterly"
}, {
"empId": "10001",
"tier": "Single",
"someting": 6,
"anything": 0,
"frequency": "Quaterly"
}
]
别忘了添加consumes
标签:
@RequestMapping(value = "/getEmployeeList", method = RequestMethod.POST, consumes="application/json", produces = "application/json")
public List<Employee> getEmployeeDataList(@RequestBody Employee[] employeearray) { ... }