Question

我的想法是创建一个简单的地址脚本，这意味着，您将邮政编码放在上面并使用相同的邮政编码获取地址。

我收到三条错误消息：

警告：在第20行的/var/www/tabelle/eingabe2/index.php中为foreach()提供的参数无效

注意：第28行/var/www/tabelle/eingabe2/index.php中的未定义索引：suche

致命错误：在第31行的/var/www/tabelle/eingabe2/index.php中的非对象上调用成员函数quote()

<!doctype html>
<html>
    <head>
        <meta charset="utf-8">
        <meta name="description" content="Adressen Datenbank">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <title>Testside</title>
        <link rel="stylesheet" href="css/style.css">
        <link rel="author" href="humans.txt">
    </head>
    <body>
    <h1>Testside</h1>
    <form action="<? echo $PHP_SELF?>" method= "POST">
        <textarea cols="10" rows="1" name="suche" wrap=virtual></textarea>
        <input type="submit" value="Suchen">
    </form>
<?php
try {
    $dbh = new PDO('mysql:host=localhost;dbname=dbaname', 'user', 'pass');
    foreach($dbh->query('SELECT * from pizzadb2') as $row) {
        print_r($row);
    }
    $dbh = null;
} catch (PDOException $e) {
    print "Error!: " . $e->getMessage() . "<br/>";
    die();
}
$suche = ($_POST['suche']);

$sql = "SELECT laden_name, vorwahl, telenr1, plz, ort, 
linkname1, forum_link FROM pizzeria_table WHERE plz = " .$dbh->quote($suche);

#FROM pizzeria_table";
#$result = mysql_query($sql);
$result = $dbh->query($sql,PDO::FETCH_ASSOC);
if (!$result || $result->rowCount()==0) { 
echo "<p>Keine Datensätze gefunden</p>\n";
}


$felder = mysql_num_fields($result);
$datensaetze = mysql_num_rows($result);
echo "<p>Anzahl der Datensätze: <b>$datensaetze</b></p>\n";
echo "<table border='1' cellspacing='0'>\n"; // Tabelle beginnen
echo "<tr>"; // Zeile erzeugen
for ($i = 0;$i < $felder;$i++) {
    $feldname = mysql_field_name($result, $i);
    echo "<th>$feldname</th>";
} 
echo "</tr>\n"; // Zeile schließen

while ($row = mysql_fetch_assoc($result)) {
    echo "<tr>"; // Zeile erzeugen
    foreach ($row as $key => $value) {
        echo "<td>$value&nbsp;</td>";
    } 
    echo "</tr>\n"; // Zeile schließen
} 
echo "</table>\n"; // Tabelle schließen
mysql_close($dp);
?>

    </body>
</html>

Answer 1

你正在使用PDO绝对错误的方式。基本问题是：

您必须在
您应该使用预准备语句而不是手动引用值
你不应该杀死你的PDO连接。
你不应该在这里使用try / catch
PHP中没有自动全局变量。

所以这就是

<?php

$dbh = new PDO('mysql:host=localhost;dbname=dbaname', 'user', 'pass');
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
$dbh->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);

$shuchen = $dbh->query('SELECT * from pizzadb2')->fetchAll();
?>
<!doctype html>
<html>
<head>
    <meta charset="utf-8">
    <meta name="description" content="Adressen Datenbank">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Testside</title>
    <link rel="stylesheet" href="css/style.css">
    <link rel="author" href="humans.txt">
</head>
<body>
<h1>Testside</h1>
<form>
    <select name="suche">
    <?php foreach ($suchen as $suche): ?>
        <option><?=$suche?></option>
    <?php endforeach ?>
    </select>
    <input type="submit" value="Suchen">
</form>
<?php
if (!isset($_GET['suche'])) die;

$sql = "SELECT laden_name, vorwahl, telenr1, plz, ort, linkname1, forum_link 
        FROM pizzeria_table WHERE plz = ?";
$stmt = $dbh->prepare($sql);
$stmt->execute([$_GET['suche']]);
$data = $stmt->fetchAll();
if (!$data) { 
    echo "<p>Keine Datensätze gefunden</p>\n";
} else {
    echo "<p>Anzahl der Datensätze: <b>$datensaetze</b></p>\n";
    echo "<table border='1' cellspacing='0'>\n"; // Tabelle beginnen
    echo "<tr>"; // Zeile erzeugen
    foreach (array_keys($data[0]) as $feldname) {
        echo "<th>$feldname</th>";
    } 
    echo "</tr>"; // Zeile erzeugen
    foreach ($data as $row) {
        echo "<tr>"; // Zeile erzeugen
        foreach ($row as $value) {
            echo "<td>$value&nbsp;</td>";
        } 
        echo "</tr>\n"; // Zeile schließen
    } 
    echo "</table>\n"; // Tabelle schließen
}

上次修改以修复上一个错误

Answer 2

您收到的错误表明您的查询失败 - 它不会引发异常，但会导致->query()返回false，这显然不是有效foreach参数！

您应该做的是将查询结果分配给变量并检查它：

$result = $dbh->query("select * from pizzadb2");
if($result === false) throw new PDOException(var_export($dbh->errorInfo(),true));
foreach($result as $row) {
    print_r($row);
}

＆＃39;参数无效......＆＃39;导致致命错误：调用非对象

2 个答案: