你能帮助我吗执行时有一个问题被php检测到,但我认为我的代码没问题。
错误说“可捕获的致命错误:类stdClass的对象无法在第46行的C:\ Program Files \ wamp \ www \ getkongregate.php中转换为字符串”
kongregate xml网站:here
这是我的代码:
<?php
$xml = simplexml_load_string(file_get_contents('http://www.kongregate.com/games_for_your_site.xml'));
$json = json_encode($xml);
$games = json_decode($json);
$count = 0;
foreach ($games->game as $game) {
echo $game->id . "\n";
echo $game->title . "\n";
echo $game->thumbnail . "\n";
echo $game->launch_date . "\n";
echo $game->category . "\n";
if (array_key_exists('screenshot',$game)) {
for($i=0;$i<=(count($game->screenshot)-1);$i++) {
echo $game->screenshot[$i] . "\n";
}
}
echo $game->flash_file . "\n";
echo $game->width . "\n";
echo $game->height . "\n";
echo $game->description . "\n";
echo $game->instructions . "\n";
echo $game->gameplays . "\n";
echo $game->rating . "\n\n------\n\n";
if ($count == 100) {break;}
$count++;
}
?>
答案 0 :(得分:0)
您正在检索xml。
为什么要将其解析为json?
使用SimpleXmlElement,然后遍历xml元素以检索数据。
$xml = file_get_contents($map_url);
$simpleXmlElement = simplexml_load_string($xml);
var_dump($simpleXmlElement);
这里:: :)
$url = 'http://www.kongregate.com/games_for_your_site.xml';
$content = file_get_contents($url)
$xml = simplexml_load_string($content);
$count = 0;
foreach ($xml as $game) {
echo strval($game->id) . PHP_EOL;
echo strval($game->title) . PHP_EOL;
echo strval($game->thumbnail) . PHP_EOL;
echo strval($game->launch_date) . PHP_EOL;
echo strval($game->category) . PHP_EOL;
if (isset($game->screenshot) && is_array($game->screenshot)) {
foreach ($game->screenshot as $screenshot) {
echo strval($screenshot) . "\n";
}
}
echo strval($game->flash_file) . PHP_EOL;
echo strval($game->width) . PHP_EOL;
echo strval($game->height) . PHP_EOL;
echo strval($game->description) . PHP_EOL;
echo strval($game->instructions) . PHP_EOL;
echo strval($game->gameplays) . PHP_EOL;
echo strval($game->rating) . PHP_EOL;
if ($count >= 100) {
break;
}
$count++;
}