我有一个像这样的SQL:
SELECT TASKID, TSK_STATUSID, TSK_CODE, TSK_TITLE, TSK_REF_NO, TSK_DESCRIPTION, STS_NAME, COALESCE(USR_NAME, 'None') AS TUSERNAME
FROM T_TASK_REQUEST
LEFT JOIN T_STATUS ON T_STATUS.STATUSID=T_TASK_REQUEST.TSK_STATUSID
LEFT JOIN T_TASK_USER ON TUS_TASKID = TASKID
LEFT JOIN T_USER ON USERID = TUS_USERID
LEFT JOIN T_PROJECT ON T_PROJECT.PROJECTID=T_TASK_REQUEST.PROJECTID
WHERE TSK_STATUSID='1' AND T_TASK_REQUEST.PROJECTID='2' ORDER BY TASKID DESC LIMIT 10
目前的结果就像这个
如何将 TASKID 分组为1行, TUSERNAME 结果为:boon | danny | jack | goh | ncc
分开 | ?
在此处查看完整尺寸的IMG:http://i.stack.imgur.com/WXH3g.jpg
答案 0 :(得分:0)
修改后的确切工作SQL是:
SELECT TASKID, TSK_STATUSID, TSK_CODE, TSK_TITLE, TSK_REF_NO, TSK_DESCRIPTION, STS_NAME, GROUP_CONCAT(DISTINCT COALESCE(USR_NAME, 'None') SEPARATOR '|') AS TUSERNAME
FROM T_TASK_REQUEST
LEFT JOIN T_STATUS ON T_STATUS.STATUSID=T_TASK_REQUEST.TSK_STATUSID
LEFT JOIN T_TASK_USER ON TUS_TASKID = TASKID
LEFT JOIN T_USER ON USERID = TUS_USERID
LEFT JOIN T_PROJECT ON T_PROJECT.PROJECTID=T_TASK_REQUEST.PROJECTID
WHERE TSK_STATUSID='1' AND T_TASK_REQUEST.PROJECTID='2'
GROUP BY TASKID
ORDER BY TASKID DESC LIMIT 10
感谢@John Woo