Question

我想要隐藏已经通过的日期。

"SELECT * FROM " . USER_TABLE_NAME . " AS cu 
 INNER JOIN " . JOB_TABLE_NAME . " AS jb 
 ON jb.user_id = cu.user_id 
 WHERE cu.user_id = '$userID' 
 ORDER BY jb.job_date DESC, jb.job_tea_time DESC";

Rightnow我正在获取所有数据order by date.

日期存储在VARCHAR中，我不想改变它。

谢谢，

Answer 1

您可以使用strtodate函数将字符串转换为日期 - 之后您可以通过日期函数轻松比较它。

Answer 2

您可以使用mysql函数unix_timestamp将日期字符串（varchar）转换为unix时间戳，并且为了比较今天的日期，您可以在php中使用strtotime（＆＃39;今天＆＃39;）

"SELECT * FROM " . USER_TABLE_NAME . " AS cu INNER JOIN " . JOB_TABLE_NAME . " AS jb 
    ON jb.user_id = cu.user_id 
WHERE cu.user_id = '$userID' AND unix_timestamp(jb.jobdate) > " . strtotime('today') . "
    ORDER BY jb.job_date DESC, jb.job_tea_time DESC";

这应该有效。如果发现任何问题，请告诉我们！

Answer 3

我认为这会有所帮助

"SELECT * FROM " . USER_TABLE_NAME . " AS cu 
 INNER JOIN " . JOB_TABLE_NAME . " AS jb 
 ON jb.user_id = cu.user_id 
 WHERE cu.user_id = '$userID' AND STR_TO_DATE(jb.job_date,'%d/%m/%Y') >= now()
 ORDER BY jb.job_date DESC, jb.job_tea_time DESC;

如何隐藏已通过日期的数据

3 个答案: