我是angularJs的新手,希望在angularJs中重写一个应用程序,但我坚持这个:
我有一个带有以下标记的自定义手风琴:
<div class="accord_main_wrap" ng-controller="catController">
<div class="accord_item_wrap" ng-repeat="head in heads">
<p class="accord_head" data-notvisible="true">{{head.text}}</p>
<div class="accord_content_wrap">
<ul>
<li ng-repeat="sub in subs">{{sub.text}}</li>
</ul>
</div>
</div>
</div>
控制器:
function catController($scope, $http) {
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
$scope.heads = [];
$scope.subs = [];
$http.post(apiURL,$.param({maincat:"true"}))
.success(function(mainCatData,status,headers,config){
for(var d=0;d<mainCatData.cat.length;d++){
$scope.heads.push(mainCatData.cat[d]);
}
for(var h=0;h<$scope.heads.length;h++){
$http.post(apiURL,$.param({subcat:$scope.heads[h].id}))
.success(function(subCatdata,stat,hea,conf){
for(var s=0;s<subCatdata.cat.length;s++){
$scope.subs.push(subCatdata.cat[s]);
}
});
}
});
问题:
很明显,每个手风琴标题应该有自己的子标题。
但正如您在上面的代码中所看到的, $scope.subs
会将所有子标题混合并分配给所有手风琴。
那我怎样才能将正义的子标题分配给各自的主题?
答案 0 :(得分:1)
$scope.heads
中的每个项目都应该有一个名为subs
...
function catController($scope, $http) {
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
$scope.heads = [];
$http.post(apiURL,$.param({maincat:"true"}))
.success(function (mainCatData) {
for (var d = 0; d < mainCatData.cat.length; d++) {
var head = mainCatData.cat[d];
$scope.heads.push(head);
getSubs(head);
}
});
function getSubs(head) {
head.subs = [];
$http.post(apiURL, $.param({subcat: head.id}))
.success(function (subCatdata) {
for (var s = 0; s < subCatdata.cat.length; s++) {
head.subs.push(subCatdata.cat[s]);
}
});
}
}