Question

以下代码效果很好，但我认为它过于复杂。

SmsBroadcastReceiver.java

public class SmsBroadcastReceiver extends BroadcastReceiver{

    private static final String ACTION = "android.provider.Telephony.SMS_RECEIVED";

    public SmsBroadcastReceiver(){
    }


    @Override
    public void onReceive(Context context, Intent intent) {

        if (intent != null && intent.getAction() != null && ACTION.compareToIgnoreCase(intent.getAction()) == 0) {

            PublicPar.myContext=context;            
            Object[] pduArray = (Object[]) intent.getExtras().get("pdus");
            SmsMessage[] messages = new SmsMessage[pduArray.length];

            for (int i = 0; i < pduArray.length; i++) {
                messages[i] = SmsMessage.createFromPdu((byte[]) pduArray[i]);               
                MSms myMSms=new MSms();     
                Intent msgIntent = new Intent(context,SmsInternetServer.class); 
                HandleSMS.SetIntentOrGetFromIntent(msgIntent, myMSms, true);
                context.startService(msgIntent);
            }
        } 
    }

}

SmsInternetServer.java

public class SmsInternetServer extends IntentService {

    public SmsInternetServer() {
        super("SmsInternetServer");     
    }

    @Override
    protected void onHandleIntent(Intent intent) {
        // TODO Auto-generated method stub
        HandleSMS.HandleReceivedSMS(intent);        
    }

}

所以我把两个java文件中的两个类合并成一个，是不是可以？是否有更简单的方法来简化代码？比如匿名课。

SmsBroadcastReceiver.java

public class SmsBroadcastReceiver extends BroadcastReceiver{

    private static final String ACTION = "android.provider.Telephony.SMS_RECEIVED";

    public SmsBroadcastReceiver(){
    }


    @Override
    public void onReceive(Context context, Intent intent) {

        if (intent != null && intent.getAction() != null && ACTION.compareToIgnoreCase(intent.getAction()) == 0) {

            PublicPar.myContext=context;            
            Object[] pduArray = (Object[]) intent.getExtras().get("pdus");
            SmsMessage[] messages = new SmsMessage[pduArray.length];

            for (int i = 0; i < pduArray.length; i++) {
                messages[i] = SmsMessage.createFromPdu((byte[]) pduArray[i]);               
                MSms myMSms=new MSms();     
                Intent msgIntent = new Intent(context,SmsInternetServer.class); 
                HandleSMS.SetIntentOrGetFromIntent(msgIntent, myMSms, true);
                context.startService(msgIntent);
            }
        } 
    }

       //inner class
       class SmsInternetServer extends IntentService {

       public SmsInternetServer() {
        super("SmsInternetServer");     
       }

       @Override
       protected void onHandleIntent(Intent intent) {
        // TODO Auto-generated method stub
        HandleSMS.HandleReceivedSMS(intent);        
       }

       }

}

Answer 1

您可以在一个java文件中定义任意数量的类。仅限制就是每个文件可以有一个公共类。在您的情况下，您也可以在SmsBroadcastReceiver之外定义SMSInternet服务器。没有必要将其定义为内部类

我可以将两个java文件中的两个类合并为一个吗？

1 个答案: