Question

主要PHP文件 -

<html>
<head>
<script type="text/javascript" src="MyJS.js"></script>
<body>
<?php
    include ("connection.php");

    $result = mysqli_query($con, "SELECT * FROM stu_rec");

    while($stu = mysqli_fetch_array($result)){
        echo "<h3>" . $stu["Name"] . "<h3>";
        echo "<h3>" . $stu["FirstName"] . "<h3>";
        echo "<h3>" . $stu["SID"] . "<h3>";
        echo "<h3>" . $stu["Email"] . "<h3>";
    }
?>

<form action="insert.php" method="post">
Name: <input type="text" name="Name">
First Name: <input type="text" name="FirstName">
SID: <input type="int" name="SID">
Email: <input type="text" name="Email">
<input type="submit">
</form>

<select>
    <option id="mon" value="1"></option>
    <option id="tue" value="2"></option>
    <option id="thu" value="3"></option>
    <option id="fri" value="4"></option>
</select>
<script>
remaining();
</script>
</body>
</head>
</html>

将信息插入数据库的文件...

<?php
include ("connection.php");

$sql="INSERT INTO table1 (Name, FirstName, SID, Email)
VALUES
('$_POST[Name]','$_POST[FirstName]','$_POST[SID]','$_POST[Email]')";

if (!mysqli_query($con,$sql))
  {
  die('Error: ' . mysqli_error($con));
  }
echo "1 record added";
header('Location: MyPHP.php');

mysqli_close($con);
?>

javascript文件 -

function remaining(){
  var mon=8;
  var tue=5;
  var thu=8;
  var fri=9;
document.getElementById("mon").innerHTML = 'Monday 15:00 to 17:00 ---- ' + mon + ' seats remaining';
document.getElementById("tue").innerHTML = 'Tuesday 14:00 to 16:00 ---- ' + tue + ' seats remaining';
document.getElementById("thu").innerHTML = 'Thursday 11:00 to 13:00 ---- ' + thu + ' seats remaining';
document.getElementById("fri").innerHTML = 'Friday 10:00 to 12:00 ---- ' + fri + ' seats remaining';
}

我有4个数据库表。从下拉菜单中选择星期一后，它将插入“table1”，从下拉菜单中选择星期二后，它将插入“table2”，依此类推。请告诉我如何做到这一点...我在这方面很新。请高兴我的愚蠢错误！

感谢。

Answer 1

将菜单放在表单中，以便提交其值：

<form action="insert.php" method="post">
Name: <input type="text" name="Name">
First Name: <input type="text" name="FirstName">
SID: <input type="int" name="SID">
Email: <input type="text" name="Email">
<select name="day">
    <option id="mon" value="1"></option>
    <option id="tue" value="2"></option>
    <option id="thu" value="3"></option>
    <option id="fri" value="4"></option>
</select>
<input type="submit">
</form>

然后在PHP中，你可以这样做：

$table = "table" . $_POST['day'];
$sql="INSERT INTO $table (Name, FirstName, SID, Email)
    VALUES
    ('$_POST[Name]','$_POST[FirstName]','$_POST[SID]','$_POST[Email]')";

Answer 2

为选择添加名称：

<select name="my_select_name">

然后相应地更改插入查询的第一行：

$sql="INSERT INTO table".$_POST['my_select_name']." (Name, FirstName, SID, Email)

但是请注意，在将数据插入数据库之前，不要对从用户检索的数据进行任何过滤，这非常危险并且可以使用错误/ SQL注入

插入特定表格

2 个答案: