Question

首先，我必须为糟糕的主题文字道歉，但我没有更好的主意。也许正因为如此，我在网上搜索时找不到解决方案。

我有2个表：主人和详细信息谁当然掌握了外键。我想从master和字段中获取所有行和所有字段以及特定记录的详细信息（假设某些列的顺序）。

我试过这样：

SELECT master.id, master.title, temp2.master_id, temp2.datetime, temp2.title_details
FROM master
LEFT JOIN (SELECT master_id, datetime, title AS title_details FROM details ORDER BY datetime DESC) temp2 ON temp2.master_id=master.id

//and this:
SELECT master.id, master.title, 
(SELECT master_id, datetime, title AS title_details FROM details WHERE master.id=details.master_id ORDER BY datetime DESC) 
FROM master
//but of course: subquery must return only one column

但这不起作用。

示例我要做的事情：

Master:
id  title
1   test
2   blab
3   something

Details:
id  master_id   datetime    title
1   1           2004-...    t: 1.1
2   1           2005-...    t: 2.1
3   1           2006-...    t: 3.1
4   2           2004-...    t: 4.2
5   2           2005-...    t: 5.2
6   3           2006-...    t: 6.3  

Expected output:
id  title       datetime    title_details
1   test        2006-...        t: 3.1
2   blab        2005-...        t: 5.2
3   something   2006-...        t: 6.3

因为我很难解释我需要什么，这里是PHP代码（从头开始）我不想做的事情：

$q = Database::$DB->prepare("SELECT * FROM master");
$q2 = Database::$DB->prepare("SELECT * FROM details WHERE master_id=? ORDER BY datetime DESC LIMIT 1");
$rows = $q->execute();
foreach ($rows as $row)
{
    $q2->execute($row->id);
    $row->AdditionalFields = $q2->fetch();
}

换句话说，我不想迭代所有主行并为特定的ONE记录选择数据（最后 - ORDER BY datetime）。

我尝试了所有不同的UNION，JOINS和SUBQUERIES，但没有成功。

已编辑（对不同答案的评论）：

实际查询是：

SELECT DISTINCT ON (todo_topics.id) todo_topics.id, todo_topics.user_id, users.username AS author, todo_topics.title, todo_topics.datetime_created, todo_topics.version, todo_topics.todo_status_id, todo_statuses.icon_image, 
    todo_topics.version_status_changed, todo_posts.text, u.username AS last_poster, todo_posts.user_id as last_poster_id
FROM todo_topics
LEFT JOIN todo_statuses ON todo_statuses.id = todo_topics.todo_status_id
LEFT JOIN users ON users.id = todo_topics.user_id
LEFT JOIN todo_posts ON todo_topics.id=todo_posts.todo_topic_id
LEFT JOIN users u ON u.id = todo_posts.user_id
ORDER BY todo_topics.id, todo_posts.datetime_created  DESC

“总运行时间：0.863 ms”

    SELECT
      todo_topics.id, todo_topics.user_id, users.username AS author, todo_topics.title, todo_topics.datetime_created, todo_topics.version, todo_topics.todo_status_id, todo_statuses.icon_image, 
        todo_topics.version_status_changed, todo_posts.text, u.username AS last_poster, todo_posts.user_id as last_poster_id
    FROM
      todo_topics
      LEFT JOIN todo_statuses ON todo_statuses.id = todo_topics.todo_status_id
    LEFT JOIN users ON users.id = todo_topics.user_id

    INNER JOIN
    (
      SELECT
        *,
        ROW_NUMBER() OVER (PARTITION BY todo_topic_id ORDER BY datetime_created DESC) AS ordinal
      FROM
        todo_posts
    )
      AS todo_posts
        ON todo_posts.todo_topic_id = todo_topics.id
    LEFT JOIN users u ON u.id = todo_posts.user_id
    WHERE
      todo_posts.ordinal = 1

“总运行时间：1.281毫秒”

 SELECT
  todo_topics.id, todo_topics.user_id, users.username AS author, todo_topics.title, todo_topics.datetime_created, todo_topics.version, todo_topics.todo_status_id, todo_statuses.icon_image, 
    todo_topics.version_status_changed, todo_posts.text, u.username AS last_poster, todo_posts.user_id as last_poster_id
FROM
  todo_topics
LEFT JOIN todo_statuses ON todo_statuses.id = todo_topics.todo_status_id
LEFT JOIN users ON users.id = todo_topics.user_id
INNER JOIN
(
  SELECT
    todo_topic_id,
    MAX(datetime_created)  AS max_datetime
  FROM
    todo_posts
  GROUP BY
    todo_topic_id
)
  AS details_lookup
    ON  details_lookup.todo_topic_id = todo_topics.id
INNER JOIN
  todo_posts
    ON  todo_posts.todo_topic_id = details_lookup.todo_topic_id
    AND todo_posts.datetime_created  = details_lookup.max_datetime
LEFT JOIN users u ON u.id = todo_posts.user_id

“总运行时间：1.143毫秒”

如果有人想知道这个时间对特定硬件意味着什么：

数据库是实验性的（每个表中的一些记录 - ＆lt; 100）在Windows 7 localhost，Intel I7 3,4GHz，16GB ram，PostgreSQL 9.3.4（默认安装）上运行

Answer 1

SELECT
  *
FROM
  master
INNER JOIN
(
  SELECT
    *,
    ROW_NUMBER() OVER (PARTITION BY master_id ORDER BY datetime DESC) AS ordinal
  FROM
    details
)
  AS details
    ON details.master_id = master.id
WHERE
  details.ordinal = 1

或者...

SELECT
  *
FROM
  master
INNER JOIN
(
  SELECT
    master_id,
    MAX(datetime)  AS max_datetime
  FROM
    details
  GROUP BY
    master_id
)
  AS details_lookup
    ON  details_lookup.master_id = master.id
INNER JOIN
  details
    ON  details.master_id = details_lookup.master_id
    AND details.datetime  = details_lookup.max_datetime

Answer 2

使用DISTINCT ON更简单：

SELECT DISTINCT ON (m.id)
       m.*, d.datetime, d.title AS title_details
FROM   master m
LEFT   JOIN details d ON d.master_id = m.id
ORDER  BY m.id, d.datetime DESC;

假设master.id为主键，details.datetime为NOT NULL。
详细说明：
Select first row in each GROUP BY group?

如果datetime可以为NULL，请小心。在这种情况下，您可能需要NULLS LAST。

PostgreSQL选择主记录并显示特定记录的详细信息列

2 个答案: