Question

我不太确定在标题中说明问题的更好/更明确的方式，所以请原谅我。

我目前正在尝试做的是根据用户的输入更改变量的值。目前我可以根据输入设置一个值，但是我的程序需要一个循环，用户必须多次输入。

我遇到的问题是，当我调用该类时，它只返回第一个输入的相关数据。因此，当用户可以继续进行不同的输入时，数据永远不会超过第一个输入。

import java.util.Scanner;

public class Hw6Wargolet {
   public static void main(String[] args) {
    Scanner keyboard = new Scanner (System.in); 
    String buddyName;
    String userChoice;

    System.out.print("Nurse: The Patient's first name is ");
    buddyName = keyboard.nextLine();

    System.out.print("You: Let's see, I should (C)hange " + buddyName + "'s bandages," +
                       "(G)ive " + buddyName + " pain medication, " + 
                    "(A)dd antibiotics to " + buddyName + "'s I.V," +
                    " or (D)ischarge " + buddyName + " ");

     userChoice = keyboard.nextLine();

     Buddy score = new Buddy(userChoice);
     BuddyScore finalScore = new BuddyScore();
     //the loop. essentially repeating the prompt for input until a score is reached
     do{
        System.out.print("You: Let's see, I should (C)hange " + buddyName + "'s"
                + " bandages, (G)ive " + buddyName + " pain medication, " + 
                    "(A)dd antibiotics to " + buddyName + "'s I.V," +
                    " or (D)ischarge " + buddyName + " ");

        userChoice = keyboard.nextLine();

        System.out.println(score.getBuddyScore());
        System.out.println(finalScore.getFinalScore());
    }while(finalScore.getFinalScore() < 5);

   }

}

下面是我的类，它返回数据/值。

public class Buddy {
    private String userChoice;
    public int buddyScore;  

    public Buddy(String userChoice){
        this.userChoice = userChoice;
    }

    public void setUserChoice(String userChoice){
        this.userChoice = userChoice;
    }

    public String getUserChoice(){
        return userChoice;
    }

    public void setBuddyScore(int buddyScore){
        buddyScore = buddyScore;
    }

    public int getBuddyScore(){
        switch (userChoice){
            case "C":
              buddyScore = 1;
              break;
            case "G":
              buddyScore = -2;
              break;
            case "A":
              buddyScore = 3;
              break;
            case "D":
              buddyScore = 7;
              break;
            default:
              buddyScore = 0;
              break;
        };
        return buddyScore; 
    }

}

此外，下面是获取每个输入分数和加总/减去总分

的类

public class BuddyScore {
   public int finalScore;
   private int buddyScore;

   public BuddyScore(){
      this.finalScore = finalScore;
      this.buddyScore = buddyScore;
   }

   public BuddyScore(Buddy object2){
      buddyScore = object2.getBuddyScore();
   }


   public void setFinalScore(int finalScore){
      this.finalScore = finalScore;
   } 

   public int getFinalScore(){
     return finalScore += buddyScore; 
   }    
}

任何建议，提示和建议都将非常感激。谢谢。

Answer 1

我注意到有三件事：

<强> 1）

在您的Buddy课程中，您使用的方法setBuddyScore(int buddyScore)

buddyscore = buddyscore;

而不是

this.buddyscore = buddyscore;

（可能会导致成员变量和参数混淆）

2）（编辑）

在您的主课程中，新userChoice没有任何反应。也许你可以这样做：

首先更改BuddyScore类，以便它存储整个Buddy对象而不是仅存储得分。这样，BuddyScore对象类知道 Buddy对象的更改位置。然后，您需要在getBuddyScore()内调用getFinalScore()方法，以便始终添加当前分数。

public class BuddyScore {
    private Buddy buddyScore;

    public BuddyScore(Buddy buddyScore) {
        this.buddyScore = buddyScore;      // here you store the 'reference' of your Buddy object
    }

    public int getFinalScore() {
        return finalScore += buddyScore.getBuddyScore();  // here you retrieve the most recent 'buddyScore' from your 'Buddy' object and add it to the finalScore
    } 
}

然后回到主要课程中，您需要更新Buddy对象（在循环内）以始终知道最新的userChoice：

do {
    // stuff
    userChoice = keyboard.nextLine();
    score.setUserChoice(userChoice);
}while (finalScore.getFinalScore() < 5);   // here your finalScore object will add the recent score from the buddy class to the final score

这实际上有效。但请注意，只有在致电getFinalScore()时才会更新您的最终得分...也许您应该引入另一种方法进行更新，并让getFinalScore()仅返回已计算的最终得分。

Answer 2

当您致电本声明时：

 userChoice = keyboard.nextLine();

您正在将该输入分配给变量userChoice。然后再打电话

userChoice = keyboard.nextLine();

将新输入重新分配给覆盖前一个变量的同一个变量。尝试更改第二个变量的名称，否则您每次只会得到相同的响应。

Java-基于用户输入更新类的返回数据

2 个答案: