Question

鉴于面向对象层次结构的模型过于简单：

var BaseObj = function (field) { this.field = field; };

var DescendentObject = function (field, field2) { 
  this.BaseObj(field); 
  this.field2 = field2; 
};

BaseObj.prototype = {
  ///<field name="field" type="String">I am well documented</field>
  field : ""
};

DescendentObject.prototype = {
  ///<field name="field" type="String">I am well documented</field>
  field2 : ""
};

//this simplies our actual inheritance model but effectively does the same thing
DescendentObject.prototype.BaseObj = BaseObj;
DescendentObject.prototype.field = BaseObj.prototype.field;

var x = new DescendentObject();
x.field2    //I am well documented
x.field     //editor knows I exist, but I am completely undocumented!

有没有办法将BaseObj中字段的优秀文档放入DescendentObject中的字段，而无需显式列出两个对象中的每个字段？

Answer 1

你可以把put实例intellisense放在BaseObj

上

var BaseObj = function (field) {
    ///<field name="field" type="String">I am well documented</field>
    this.field = field;
};

或使用非对象文字符号：

DescendentObject.prototype = new (function(){
    /// <field name="field" type="String">I am well documented</field>
    this.field2 = "";
})();

根据此处的文件：http://msdn.microsoft.com/en-us/library/hh542725.aspx，此注释忽略name属性并自动附加到其下面的任何内容，因为它位于对象文字内：

DescendentObject.prototype = {
  ///<field name="field" type="String">I am well documented</field>
  field2 : ""
};

Visual Studio JavaScript IntelliSense - 在面向对象模型中工作

1 个答案: