Question

我正在尝试在控制器中设置超时，这样如果在250ms内没有收到响应，它就会失败。我已将单位测试设置为超时10000，以便满足此条件，任何人都可以指出我正确的方向吗？（编辑我试图实现这一点，而不使用$ http服务，我知道提供超时功能）

（编辑 - 我的其他单元测试失败了，因为我没有调用timeout.flush，现在我只需要在promiseService.getPromise（）返回未定义的promise时获取超时消息。我已从问题中删除了早期代码。）

promiseService（promise是一个测试套件变量，允许我在应用之前对每个测试套件中的promise使用不同的行为，例如拒绝一个，成功另一个）

    mockPromiseService = jasmine.createSpyObj('promiseService', ['getPromise']);
    mockPromiseService.getPromise.andCallFake( function() {
        promise = $q.defer();
        return promise.promise;
    })

正在测试的控制器功能 -

$scope.qPromiseCall = function() {
    var timeoutdata = null;
    $timeout(function() {
        promise = promiseService.getPromise();
        promise.then(function (data) {
                timeoutdata = data;
                if (data == "promise success!") {
                    console.log("success");
                } else {
                    console.log("function failure");
                }
            }, function (error) {
                console.log("promise failure")
            }

        )
    }, 250).then(function (data) {
        if(typeof timeoutdata === "undefined" ) {
            console.log("Timed out")
        }
    },function( error ){
        console.log("timed out!");
    });
}

测试（通常我在这里解决或拒绝承诺但是没有设置它我正在模拟超时）

it('Timeout logs promise failure', function(){
    spyOn(console, 'log');
    scope.qPromiseCall();
    $timeout.flush(251);
    $rootScope.$apply();
    expect(console.log).toHaveBeenCalledWith("Timed out");
})

Answer 1

首先，我想说你的控制器实现应该是这样的：

$scope.qPromiseCall = function() {

    var timeoutPromise = $timeout(function() {
      canceler.resolve(); //aborts the request when timed out
      console.log("Timed out");
    }, 250); //we set a timeout for 250ms and store the promise in order to be cancelled later if the data does not arrive within 250ms

    var canceler = $q.defer();
    $http.get("data.js", {timeout: canceler.promise} ).success(function(data){
      console.log(data);

      $timeout.cancel(timeoutPromise); //cancel the timer when we get a response within 250ms
    });
  }

您的测试：

it('Timeout occurs', function() {
    spyOn(console, 'log');
    $scope.qPromiseCall();
    $timeout.flush(251); //timeout occurs after 251ms
    //there is no http response to flush because we cancel the response in our code. Trying to  call $httpBackend.flush(); will throw an exception and fail the test
    $scope.$apply();
    expect(console.log).toHaveBeenCalledWith("Timed out");
  })

  it('Timeout does not occur', function() {
    spyOn(console, 'log');
    $scope.qPromiseCall();
    $timeout.flush(230); //set the timeout to occur after 230ms
    $httpBackend.flush(); //the response arrives before the timeout
    $scope.$apply();
    expect(console.log).not.toHaveBeenCalledWith("Timed out");
  })

DEMO

promiseService.getPromise的另一个例子：

app.factory("promiseService", function($q,$timeout,$http) {
  return {
    getPromise: function() {
      var timeoutPromise = $timeout(function() {
        console.log("Timed out");

        defer.reject("Timed out"); //reject the service in case of timeout
      }, 250);

      var defer = $q.defer();//in a real implementation, we would call an async function and 
                             // resolve the promise after the async function finishes

      $timeout(function(data){//simulating an asynch function. In your app, it could be
                              // $http or something else (this external service should be injected
                              //so that we can mock it in unit testing)
        $timeout.cancel(timeoutPromise); //cancel the timeout 

         defer.resolve(data);
      });

      return defer.promise;
    }
  };
});

app.controller('MainCtrl', function($scope, $timeout, promiseService) {

  $scope.qPromiseCall = function() {

    promiseService.getPromise().then(function(data) {
      console.log(data); 
    });//you could pass a second callback to handle error cases including timeout

  }
});

您的测试与上面的示例类似：

it('Timeout occurs', function() {
    spyOn(console, 'log');
    spyOn($timeout, 'cancel');
    $scope.qPromiseCall();
    $timeout.flush(251); //set it to timeout
    $scope.$apply();
    expect(console.log).toHaveBeenCalledWith("Timed out");
  //expect($timeout.cancel).not.toHaveBeenCalled(); 
  //I also use $timeout to simulate in the code so I cannot check it here because the $timeout is flushed
  //In real app, it is a different service
  })

it('Timeout does not occur', function() {
    spyOn(console, 'log');
    spyOn($timeout, 'cancel');
    $scope.qPromiseCall();
    $timeout.flush(230);//not timeout
    $scope.$apply();
    expect(console.log).not.toHaveBeenCalledWith("Timed out");
    expect($timeout.cancel).toHaveBeenCalled(); //also need to check whether cancel is called
  })

DEMO

Answer 2

“未通过承诺除非在指定的时间范围内解决”的行为似乎是重构为单独服务/工厂的理想选择。这应该使新服务/工厂和控制器中的代码更清晰，更可重复使用。

控制器，我假设只是在范围内设置成功/失败：

app.controller('MainCtrl', function($scope, failUnlessResolvedWithin, myPromiseService) {
  failUnlessResolvedWithin(function() {
    return myPromiseService.getPromise();
  }, 250).then(function(result) {
    $scope.result = result;
  }, function(error) {
    $scope.error = error;
  });
});

工厂failUnlessResolvedWithin创造了一个新的承诺，它有效地“拦截”来自传递函数的承诺。它返回一个新的，它复制了它的解析/拒绝行为，除了它还拒绝了在超时内没有解决的promise：

app.factory('failUnlessResolvedWithin', function($q, $timeout) {

  return function(func, time) {
    var deferred = $q.defer();

    $timeout(function() {
      deferred.reject('Not resolved within ' + time);
    }, time);

    $q.when(func()).then(function(results) {
      deferred.resolve(results);
    }, function(failure) {
      deferred.reject(failure);
    });

    return deferred.promise;
  };
});

这些测试有点棘手（很长），但你可以在http://plnkr.co/edit/3e4htwMI5fh595ggZY7h?p=preview看到它们。测试的要点是

控制器的测试通过调用failUnlessResolvedWithin来嘲笑$timeout。
```
$provide.value('failUnlessResolvedWithin', function(func, time) {
  return $timeout(func, time);
});
```
这是可能的，因为'failUnlessResolvedWithin'（故意）在句法上等同于$timeout，并且已完成，因为$timeout提供flush函数来测试各种情况。

服务本身的测试使用调用$timeout.flush来测试在超时之前/之后解析/拒绝的原始承诺的各种情况的行为。

beforeEach(function() {
  failUnlessResolvedWithin(func, 2)
  .catch(function(error) {
    failResult = error;
  });
});

beforeEach(function() {
  $timeout.flush(3);
  $rootScope.$digest();
});

it('the failure callback should be called with the error from the service', function() {
  expect(failResult).toBe('Not resolved within 2');
});

您可以在http://plnkr.co/edit/3e4htwMI5fh595ggZY7h?p=preview

看到这一切

Answer 3

我实现了@Michal Charemza的failUnlessResolvedWithin和一个真实的样本。通过将延迟对象传递给func，它减少了必须在使用代码中实例化一个承诺＆＃34; ByUserPosition＆＃34;。帮助我处理firefox和地理位置。

.factory('failUnlessResolvedWithin', ['$q', '$timeout', function ($q, $timeout) {

    return function(func, time) {
        var deferred = $q.defer();

        $timeout(function() {
            deferred.reject('Not resolved within ' + time);
        }, time);

        func(deferred);

        return deferred.promise;
    }
}])



            $scope.ByUserPosition = function () {
                var resolveBy = 1000 * 30;
                failUnlessResolvedWithin(function (deferred) {
                    navigator.geolocation.getCurrentPosition(
                    function (position) {
                        deferred.resolve({ latitude: position.coords.latitude, longitude: position.coords.longitude });
                    },
                    function (err) {
                        deferred.reject(err);
                    }, {
                        enableHighAccuracy : true,
                        timeout: resolveBy,
                        maximumAge: 0
                    });

                }, resolveBy).then(findByPosition, function (data) {
                    console.log('error', data);
                });
            };

在angularjs中为promise设置超时处理程序

3 个答案: