Question

您好我需要知道＆＃34;如何使用Libxml2＆＃34;在C ++中读取xml文件的一部分。在我的xml文件中，我有：

<svg>
    <g>
       <path d="11"/>
    </g>
</svg>

我希望看到＆＃34; d＆＃34;在我的c ++程序中，当我到达这一点时：

   xmlNode *cur_node = NULL;

    for (cur_node = a_node; cur_node; cur_node = cur_node->next) {

      if(xmlStrEqual(xmlCharStrdup("path"),cur_node->name)){


            printf("element: %s\n", cur_node->name);
        }

        print_element_names(cur_node->children);
    }    
}

我不知道我需要做什么，请帮助我。

Answer 1

我不确定我是否理解这个问题，但听起来你想在元素“path”中打印属性“d”。在上面的代码中，您需要这样的内容：

xmlChar *d = xmlGetProp(cur_node, "d");
... do something ...
xmlFree(d);

Answer 2

类似的东西？

static void
print_element_names(xmlNode * a_node)

{

   xmlNode *cur_node = NULL;
   xmlChar        *d;

   for (cur_node = a_node; cur_node; cur_node = cur_node->next) {    

      if(xmlStrEqual(xmlCharStrdup("path"),cur_node->name)){ 
          printf("element: %s\n", cur_node->name);
      }

      print_element_names(cur_node->children);  

      if(xmlGetProp(cur_node, "d")){  

      printf("wspolrzedne: %s\n", d);
   }

   xmlFree(d);
}

Answer 3

下面的函数将读取包含节点和值的完整xml，

int readxml(xmlDocPtr pFilePointer,xmlNodePtr pNodePointer) {
  while (pNodePointer != NULL) {
    if ((xmlStrcmp(pNodePointer->name, (const xmlChar *)"text"))) {
      printf("%s\n", pNodePointer->name);
    } else {
    }
    if (NULL != pNodePointer->xmlChildrenNode) {
      pNodePointer = pNodePointer->xmlChildrenNode;
      if ((!xmlStrcmp(pNodePointer->name, (const xmlChar *)"text"))) {
        string node;
        xmlNodeListGetStringWrapper(pFilePointer, pNodePointer, node);
        printf("%s\n", node.c_str());
        continue;
      }
    } else if (pNodePointer->next != NULL) {
      pNodePointer = pNodePointer->next;
    } else {
      pNodePointer = pNodePointer->parent;
      pNodePointer = pNodePointer->next;
    }
  }
  return 0;
}

如何使用Libxml2在C ++中读取xml文件的一部分

3 个答案: