Question

我希望在javascript中获得前一周的第一天（星期一）和最后一天（星期日）。我已经检查了其他主题，但它不起作用。如果前一周是2个不同的月份，我还需要处理。

我使用此代码，但是lastsunday是06/03/2014而不是06/04/2014

var beforeOneWeek = new Date(new Date().getTime() - 60 * 60 * 24 * 7 * 1000)
  , day = beforeOneWeek.getDay()
  , diffToMonday = beforeOneWeek.getDate() - day + (day === 0 ? -6 : 1)
  , lastMonday = new Date(beforeOneWeek.setDate(diffToMonday))
  , lastSunday = new Date(beforeOneWeek.setDate(diffToMonday + 6));

$( "#dateDebut" ).val($.datepicker.formatDate('dd/mm/yy', lastMonday));
$( "#dateFin" ).val($.datepicker.formatDate('dd/mm/yy', lastSunday));

Answer 1

您必须克隆beforeOneWeek。其他一切看起来都在你的代码中

var beforeOneWeek = new Date(new Date().getTime() - 60 * 60 * 24 * 7 * 1000)
var beforeOneWeek2 = new Date(beforeOneWeek);
  day = beforeOneWeek.getDay()
  diffToMonday = beforeOneWeek.getDate() - day + (day === 0 ? -6 : 1)
  lastMonday = new Date(beforeOneWeek.setDate(diffToMonday))
  lastSunday = new Date(beforeOneWeek2.setDate(diffToMonday + 6));

$( "#dateDebut" ).val($.datepicker.formatDate('dd/mm/yy', lastMonday));
$( "#dateFin" ).val($.datepicker.formatDate('dd/mm/yy', lastSunday));

Answer 2

以下是代码：

var _now = new Date();

// get sunday by subtraction current week day from month day
var sunday = new Date(_now.setDate(_now.getDate() - _now.getDay()));
// get monday by subtraction 6 days from sunday
var monday = new Date(_now.setDate(_now.getDate() - 6));
var isDifferentMonth = sunday.getMonth() !== monday.getMonth();

详细了解日期函数here。

javascript获取前一周的第一天和最后一天

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