Question

这是我的OrderedDict对象，

a=OrderedDict([(u'p', [u'"The Exam Room" is a new series in which everyday medical questions are answered by physicians and professors from the Yale School of Medicine.', u'In our second episode: Dr. Stephen Strittmatter, Vincent Coates Professor of Neurology and director of the Adler Memory Clinic in Neurology, explains when memory loss can become a problem and what you can do to boost your brain power.', OrderedDict([(u'em', u'Produced &amp; Hosted by Noah Golden')])])])

我要做的是从这个对象获取文本，

>>> a.get('p')

获得输出，

[u'"The Exam Room" is a new series in which everyday medical questions are answered by physicians and professors from the Yale School of Medicine.', u'In our second episode: Dr. Stephen Strittmatter, Vincent Coates Professor of Neurology and director of the Adler Memory Clinic in Neurology, explains when memory loss can become a problem and what you can do to boost your brain power.', OrderedDict([(u'em', u'Produced &amp; Hosted by Noah Golden')])]

但结果文本也包含一个OrderedDict。

如何合并OrderedDict，

中的文字

预期产出：

The Exam Room" is a new series in which everyday medical questions are answered by physicians and professors from the Yale School of Medicine.', u'In our second episode: Dr. Stephen Strittmatter, Vincent Coates Professor of Neurology and director of the Adler Memory Clinic in Neurology, explains when memory loss can become a problem and what you can do to boost your brain power. Produced &amp; Hosted by Noah Golden

Answer 1

如果你事先不知道类型的嵌套，那么这里的关键是递归。这是一个示例（格式化文本以便于阅读）：

#!/usr/bin/env python

import collections

a = collections.OrderedDict([(u'p', [u""" 
    "The Exam Room" is a new series in
    which everyday medical questions are answered by physicians and 
    professors from the Yale School of Medicine.""", 
    u"""In our second episode: Dr. Stephen Strittmatter,
    Vincent Coates Professor of Neurology and director of
    the Adler Memory Clinic in Neurology, explains when 
    memory loss can become a problem and what you can do to 
    boost your brain power.""", 
    collections.OrderedDict([(u'em',
        u'Produced &amp; Hosted by Noah Golden')])])])

现在展平对象，可能是映射或列表。实现了三个选项：如果找到的值是字符串，我们只需将其附加到collector。如果是list或Mapping，我们会再次致电flatten。请注意，您可以使用allowed kwarg指定一些允许的标记：

def flatten(obj, allowed=(u'p', u'em')):
    collector = []

    def process(v, collector=collector):
        if isinstance(v, (list, collections.Mapping)):
            collector += flatten(v, allowed=allowed)
        elif isinstance(v, basestring):
            collector.append(v)
        else:
            raise ValueError('Cannot handle type: {t}'.format(t=v.__class__))

    if isinstance(obj, list):
        for v in obj:
            process(v)

    if isinstance(obj, collections.Mapping):
        for k, v in obj.iteritems():
            if k in allowed:
                process(v)

    return collector

if __name__ == '__main__':
    print(flatten(a))

您的示例的结果将是一个三元素列表，如下所示：

[u'"The Exam Room" is a new series ...',
 u'In our second episode: ...',
 u'Produced &amp; Hosted by Noah Golden']

现在，如果你想要一个字符串，只需join现在被展平的列表：

print(''.join(flatten(a)))

Answer 2

这是一个奇怪的词典，但你可以实现想要你想要的这样：

[a['p'][0],a['p'][1] + u' ' + a['p'][2]['em']]

结果：

[u'“考试室”是一个新的系列，每天都有医学问题由耶鲁大学的医生和教授回答医学。'，你在我们的第二集：Stephen Strittmatter博士，文森特科茨神经病学教授和阿德勒记忆诊所主任在神经病学中，解释当记忆丧失可能成为一个问题和什么你可以做到提高你的脑力。制作＆amp;由Noah主持金']

这会返回一个列表，正如您在问题中所要求的那样。如果你想要一个字符串：

import string
string.join([a['p'][0],a['p'][1],a['p'][2]['em']])

将导致：

“考试室”是一个新的系列，其中包含日常医疗问题由耶鲁大学的医生和教授回答医学。在我们的第二集中：Stephen Strittmatter博士，Vincent 科茨神经病学教授和阿德勒记忆诊所主任在神经病学中，解释当记忆丧失可能成为一个问题和什么你可以做到提高你的脑力。制作＆amp;由Noah主持金

在Python中将文本与嵌套的OrderedDict分开

2 个答案: