使用Picasso获取和传递图像URL

时间:2014-04-10 12:36:42

标签: android picasso loading-image

我正在尝试从用户选择的所选图像中获取图像URL,以便我可以将该字符串/ URL传递给我已设置的另一个片段,以便可以通过图像视图完全查看图像。

我怎样才能做到这一点?感谢。

这是SampleGridViewAdapter类:

inal class SampleGridViewAdapter extends BaseAdapter {
private final Context context;
public final List<String> urls = new ArrayList<String>();

public SampleGridViewAdapter(Context context) {
    this.context = context;

    // Ensure we get a different ordering of images on each run.
    Collections.addAll(urls, Data.URLS);
    Collections.shuffle(urls);



}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    SquaredImageView view = (SquaredImageView) convertView;
    if (view == null) {
        view = new SquaredImageView(context);
        view.setScaleType(CENTER_CROP);
    }

    // Get the image URL for the current position.
    String url = getItem(position);

    // Trigger the download of the URL asynchronously into the image view.
    Picasso.with(context) //
            .load(url) //
            .placeholder(R.drawable.placeholder) //
            .error(R.drawable.error) //
            .fit() //
            .into(view);

    return view;
}

@Override
public int getCount() {
    return urls.size();
}

@Override
public String getItem(int position) {
    return urls.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}
}

这是我的SampleGridViewActivity:

public class SampleGridViewActivity extends SherlockFragment {

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.sample_gridview_activity,
            container, false);

    GridView Grid = (GridView) view.findViewById(R.id.grid_view);
    Grid.setAdapter(new SampleGridViewAdapter(getActivity()));

    Grid.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                int position, long urls) {
            // TODO Auto-generated method stub

            FragmentManager fm = getFragmentManager();
            FragmentTransaction transaction = fm.beginTransaction();

            Fragment openImage = new ImageViewPager();

            transaction.replace(R.id.content_frame, openImage);

            transaction.addToBackStack(null);

            transaction.commit();

        }
    });

    return view;

}

 }

以下是我要将字符串发送到的类:

public class ImageViewer extends SherlockFragment {

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.imageviewpager, container, false);

    ImageView IMGView = (ImageView) view.findViewById(R.id.imageView1);

    Picasso.with(getActivity()).load("Pass URL into HERE").into(IMGView);

    return view;
}

}

1 个答案:

答案 0 :(得分:1)

您应该使用Argument的{​​{1}}功能。

创建Fragments时,您可以将Fragment作为参数传递

URL

然后当你的Fragment openImage = new ImageViewPager(); Bundle b = new Bundle(); b.putString("url", DATA.URLs.get(position)); openImage.setArguments(b); transaction.replace(R.id.content_frame, openImage); 被夸大时,你可以得到那个参数字符串

Fragment